Answer is- 824% all you have to do is move the decimal point two spaces to the right.
Answer:
(3, -9)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
-5x - 3y = 12
y = x - 12
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: -5x - 3(x - 12) = 12
- Distribute -3: -5x - 3x + 36 = 12
- Combine like terms: -8x + 36 = 12
- Isolate <em>x</em> term: -8x = -24
- Isolate <em>x</em>: x = 3
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = x - 12
- Substitute in <em>x</em>: y = 3 - 12
- Subtract: y = -9
<u>Step 4: Graph systems</u>
<em>Check the solution set.</em>
<span>Simplify ((1/x)-(1/y))/((1/x)+(1/y))</span>
y-x
______
y+x
Answer:
The length is 8 inches and the width is 3 inches
Step-by-step explanation:
Let w represent the width.
The length can be represented by 2w + 2
Use the area formula, A = lw, and plug in the area and the expressions for the length and width:
A = lw
24 = (2w + 2)(w)
Simplify and solve for w:
24 = 2w² + 2w
2w² + 2w - 24
Divide everything by 2:
w² + w - 12
Factor:
(w + 4)(w - 3)
Set equal to 0 and solve for each factor:
w + 4 = 0
w = -4
w - 3 = 0
w = 3
Since the width cannot be negative, the width has to be 3.
Next, find the length by plugging in 3 as w:
2w + 2
2(3) + 2
= 8
So, the length is 8 inches and the width is 3 inches