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Galina-37 [17]
3 years ago
13

10) Jackson’s scores on the first four algebra quizzes are 79, 88, 95, and 71. What score must he earn on the fifth quiz to earn

an average quiz score of 85?
Mathematics
1 answer:
Hoochie [10]3 years ago
5 0
Based on the given information, let x represent the grade for the fifth quiz.

(79+88+95+71+x)/5=85
(333+x)/5=85
333+x=425
x=92

Jackson would have to earn a 92 on his fifth quiz to earn an average of 85.
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Maslowich

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How do I solve this ?
gizmo_the_mogwai [7]

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Given: x - 5 > -2. Choose the solution set. {x | x R, x > -7} {x | x R, x > -3} {x | x R, x > 3} {x | x R, x > 7}
sweet-ann [11.9K]

Answer:

{x | x ∈ R, x > 3}

Step-by-step explanation:

We are given the following inequality:

x - 5 > -2

In order to find the solution, we have to isolate the x on one side. This can be done by adding 5 to both sides of the inequality as shown below:

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So the solution of the inequality is set of all numbers where x > 3. This is represented by 3rd option.

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3 years ago
Using the binomial theorem , obtain the expansion of :
andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1  6  15  20  15  6  1

Decreasing powers of 1 from 1^{6} to 1^{0}

Increasing powers of 3x from (3x)^{0} to (3x)^{6}

1+3x)^{6}

= 1.1^{6}(3x)^{0} + 6.1^{5}(3x)^{1} + 15.1^{4}(3x)^{2} + 20.1^{3}(3x)^{3} + 15.1²(3x)^{4} + 6.1^{1}(3x)^{5} + 1.1^{0}(3x)^{6}

= 1 + 18x + 135x² + 540x³ + 1215x^{4} + 1458x^{5} + 729x^{6}

--------------------------------------------------------------------------------------

(1-3x)^{6}

= 1.1^{6}(-3x)^{0} + 6.1^{5}(-3x)^{1} + 15.1^{4}(-3x)^{2} + 20.1^{3}(-3x)^{3} + 15.1²(-3x)^{4} + 6.1^{1}(-3x)^{5} + 1.1^{0}(-3x)^{6}

= 1 - 18x + 135x² - 540x³ + 1215x^{4} - 1458x^{5} + 729x^{6}

----------------------------------------------------------------------------------

Collecting like terms from both expressions

(1+3x)^{6} + (1-3x)^{6}

= 2 + 270x² + 2430x^{4} + 1458x^{6}

----------------------------------------------------

(2)

Using Pascal's triangle with n = 5

1  5  10  10  5  1

Decreasing powers of 1 from 1^{5} to 1^{0}

Increasing powers of 2x from (2x)^{0} to (2x)^{5}

(1+2x)^{5}

= 1.1^{5}(2x)^{0} + 5.1^{4}(2x)^{1} + 10.1^{3}(2x)^{2} + 10.1^{2}(2x)^{3} + 5.1^{1}(2x)^{4}+ 1.1^{0}(2x)^{5}

= 1 + 10x + 40x² + 80x³ + 80x^{4} + 32x^{5}

8 0
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LuckyWell [14K]

Answer:

convert 9.5

n-9=27

Step-by-step explanation:

I converted it for you.

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