Wilda can do the job in 4 hours ... she does 1/4 (or 0.25) of it each hour.
Karla can do it in 5 hours ... she does 1/5 (or 0.2) of it each hour.
Wilda worked alone for 1 hour ... 0.25 of the job was done before her helper
arrived. So only 0.75 of the job remained to be done together.
Working together, they accomplish (0.25 + 0.2) = 0.45 of the job in 1 hour.
How many times do they need to do 0.45 of the job in order to finish
the 0.75 of it that remains ? That's the number of hours it will take them,
working together.
0.75 / 0.45 = <em>1 and 2/3</em>
After Wilda worked alone for 1 hour and Karla came along to join her, it will
take them another <em>1 hour and 40 minutes</em> to finish the job and go for a swim.
In order for the triangle to be isosceles, we have to set two lengths of the triangle equal to each other.
Let's take the lengths 5x-12 and x+20 and set them equal to each other.
5x - 12 = x + 20
Combine like terms by moving them over to their respective sides.
Subtract x from both sides of the equation.
4x - 12 = 20
Add 12 to both sides of the equation.
4x = 32
Divide both sides by 4.
x = 8
Check your answer by substituting.
5x - 12 = x + 20
5(8) - 12 = 8 + 20
40 - 12 = 28
28 = 28
Solution: x = 8
There are 4 choose 3 ways to hold 3 kings and 4 possible queens to make up the fourth card of the hand out of a total of 54 choose 4 possible four-card hands, which gives us the following expression for the probability of being dealt 3 kings and a queen out of 4 cards: Or roughly 1 in every 16920 four card hands.
The equation should be 7x^2 -x-9=0
<span> Position Value of Term. 1. 4. </span>2<span>. 8. 3. </span>12<span>. 4. 16. 5. </span>20<span>. What expression shows the ... 1 1. </span>2<span> -5. </span>3 1<span>. 4 -5. 5 1. </span>B). n an<span>. 1 </span>2<span>. </span>2<span> 8. 3 14. 4 </span>20<span>. 5 26. </span>C). n an<span>. 1 </span>2<span>. </span>2<span> -</span>2<span>. 3 -10. 4 -26 ... </span>Generalize<span>the </span>pattern<span> by </span>finding<span> an explicit formula for the </span>nth term<span>. A) </span>n2<span> + 5. </span>B<span>). 3n + 1. </span>C<span>). </span>2n<span> + 5. </span>D). (n<span> + </span><span>1)</span>
