Question

I swear to god this is urgent:

Answer 1

the​ line-of-sight distance from the television camera to the base of the stadium​ is 1449.28 m .

Step-by-step explanation:

A blimp provides aerial television views of a baseball game. The television camera sights the stadium at a 12° angle of depression. The altitude of the blimp is 300 m. We need to find What is the​ line-of-sight distance from the television camera to the base of the stadium​ . Let's find out:

According to question , given scenario is in a right angle triangle where

$Perpendicular=300\\Hypotenuse=?\\x=12$ , where x is angle of depression.

We know that $sinx= \frac{Perpendicular}{Hypotenuse}$

⇒  $sin12= \frac{300}{Hypotenuse}$

⇒  $Hypotenuse= \frac{300}{Sin12}$

⇒  $Hypotenuse= \frac{300}{0.207}$

⇒  $Hypotenuse= 1449.28m$

Therefore , the​ line-of-sight distance from the television camera to the base of the stadium​ is 1449.28 m .