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siniylev [52]
3 years ago
14

Suppose that you are asked to conduct a study to determine whether smaller class

Mathematics
1 answer:
weeeeeb [17]3 years ago
8 0

Answer:

a. correlation

b. inverse linear correlation exists If the higher the population of students lead to a decrease in test score,

c. yes

Step-by-step explanation:

a. Correlation is a measure of the amount of association existing between two variables.

b. For linear correlation, if points are plotted on a graph and all the points lie on a straight line, then perfect linear correlation is said to exist. When a straight line having a positive gradient can reasonably be drawn through points on a graph positive or direct linear correlation exists,

Similarly,when a straight line having a negative gradient can reasonably be drawn through points on a graph, negative or inverse linear correlation exists,

The results of this determination give values of r lying between +1 and −1, where +1 indicates perfect direct  Positive linear correlation and −1 indicates perfect inverse correlation or Negative linear correlation and 0 indicates that no correlation exists.

If the higher the population of students lead to a decrease in test score, there will definitely be a negative correlation between class size and test score. i.e low class size result in high test score which consequently lead to high performance.

c. YES

A negative correlation means low class size result in high test score which consequently lead to better performance.

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What is the prouduct of 5/6 x 3. show work using the number line method
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5 0
3 years ago
XLiV represents 64 true ya false​
V125BC [204]

Answer:

False

Step-by-step explanation:

Given

XLIV = 64

Required

True or False

The above numeral can be split as follows:

XLIV = XL + IV

X means 10 and L means 50.

But because X (10) which is smaller comes before L (50), XL is executed as:

XL = -10 + 50

XL = 40

In Roman numerals;

IV = 4

Substitute 40 for XL and 4 for IV.

XLIV = 40 + 4

XLIV = 44

Hence;

<em />XLIV = 64<em> is false</em>

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2 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
Manuel rented a truck for one day. There was a base fee of $14.95, and there was an additional charge of 87 cents for each mile
sp2606 [1]

base fee 14.95

0.87 cents per mile

 total  =248.98

248.98-14.95 = 234.03

234.03/0.87 =269 miles

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3 years ago
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lions [1.4K]
1 centimetre=0.1 decimetre
therefore the answer is 2.5 decimetres.
3 0
3 years ago
Read 2 more answers
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