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Sindrei [870]
3 years ago
5

What is the 3rd quadrant of 10,20,30,40,50,60​

Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0

Answer:55

Step-by-step explanation: since there are basically two medians for the third quadrant, you add them and then divided by 2. 50 and 60 equal 110. 110 divided by two is 55. 55 is your third quadrant

Mademuasel [1]3 years ago
5 0

The answer is 55

Hope this helps

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solo el 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal. Si
prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
  • p es la probabilidad de éxito en un ensayo
  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
  • Llegan 10 empleados, o sea, n = 10.

La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

3 0
2 years ago
25 letters in 4 days
pentagon [3]

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What is the absolute value of 19.8?
arsen [322]

Answer:

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Step-by-step explanation:

5 0
2 years ago
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lara [203]

<u>Answer:</u>

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<u>Step-by-step explanation:</u>

We are instructed to multiply the number the number of minutes Mr. Frotout spent on long distance calls by 0.45 the long distance rate then add 33 the flat monthly charge.

Assuming the number of long minutes spent on long distance calls by Mr. Frotout to be m, we can express the given situation as follows:

0 . 4 5 m + 3 3

7 0
3 years ago
a circular racecar track has a radius ig 1.6 miles.about how many times must a car drive around the race track to drive 15 miles
madam [21]
He has to drive around the track about 1.5 times.

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We now divide 15 by this:
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8 0
3 years ago
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