Answer:
It seems like the question is not complete. So, I will asume that the complete question is: " A bomb is to be dropped along a mile-long line that stretches across a practice target. The target center is at the midpoint of the line. The target will be destroyed if the bomb falls within a tenth of a mile on either side of the center. Find the Probability that the target is destroyed if the bomb falls randomly along the line."
Step-by-step explanation:
The total of possible cases is the length of the line = 1 mi ;
The favourable cases are the two lengths of 0.1 mi = 0.2 mi ;
Assuming the bomb has no bias for any point ,
the probability of favourable cases' occurrence is 0.2/1 = 0.2
Answer:
A' (8,-7)
B' (8,-7)
When rotating a point 270 degrees counterclockwise about the origin our point A(x,y) becomes A'(y,-x). This means, we switch x and y and make x negative
Step-by-step explanation:
Hope this helps! (づ ̄3 ̄)づ╭❤~
$513 (amount earned) / 54 (amount of hours) = $9.50 (hourly rate)
to check:
$9.50 (hourly rate) x 54 (amount of hours)
= 513 (amount earned)
hope this helps :)
Given that
z₁ = 15 (cos(90°) + i sin(90°))
z₂ = 3 (cos(10°) + i sin(80°))
we get the quotient z₁/z₂ by dividing the moduli and subtracting the arguments:
z₁/z₂ = 15/3 (cos(90° - 10°) + i sin(90° - 10°))
z₁/z₂ = 5 (cos(80°) + i sin(80°))
so that z₁ is scaled by a factor of 1/3 and is rotated 10° clockwise.