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Morgarella [4.7K]
3 years ago
15

HELP ASAP

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0

Answer:

a

Step-by-step explanation:

SSSSS [86.1K]3 years ago
4 0

Answer:

who is the captain of the football team

Step-by-step explanation:

i might be wrong i havent taken a class that neads this, but all the others need a bunch of values from a group of people. this is just asking who someone is

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3 years ago
PLEASE HELP FAST!!!!!
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Step-by-step explanation:

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7 0
4 years ago
The NWBC found that 42.1% of women-owned businesses provided retirement plans contributions.
Natasha_Volkova [10]

Answer:

Sample size of 586 or higher.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

What sample size could be 95% confident that the estimated (sample) proportion is within 4 percentage points of the true population proportion?

Sample size of at least n when M = 0.04

42.1% of women-owned businesses provided retirement plans contributions, which means that p = 0.421. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.421*0.579}{n}}

0.04\sqrt{n} = 0.9677

\sqrt{n} = \frac{0.9677}{0.04}

\sqrt{n} = 24.19

\sqrt{n}^{2} = (24.19)^(2)

n = 585.2

We need a sample size of 586 or higher.

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Step-by-step explanation:

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3 years ago
Read 2 more answers
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