Earth is 1 A.U. from the sun. Scientific Notation: 4.600 x 107 km(3.075 x 10-1 A.U.)
The image is a bit hard to make out, so I'm going to make some guesses. It looks like it says
![PN=12](https://tex.z-dn.net/?f=PN%3D12)
,
![QP=8](https://tex.z-dn.net/?f=QP%3D8)
, and
![PM=17](https://tex.z-dn.net/?f=PM%3D17)
, and you're asked to find
![QR](https://tex.z-dn.net/?f=QR)
.
You know that
![\Delta NPM](https://tex.z-dn.net/?f=%5CDelta%20NPM)
and
![\Delta NQR](https://tex.z-dn.net/?f=%5CDelta%20NQR)
are similar, which means their corresponding sides are proportional in length. So there's some constant
![c](https://tex.z-dn.net/?f=c)
such that
![NP=cNQ](https://tex.z-dn.net/?f=NP%3DcNQ)
![PM=cQR](https://tex.z-dn.net/?f=PM%3DcQR)
![MN=cRN](https://tex.z-dn.net/?f=MN%3DcRN)
To find
![QR](https://tex.z-dn.net/?f=QR)
, you need to know
![PM](https://tex.z-dn.net/?f=PM)
and the constant
![c](https://tex.z-dn.net/?f=c)
.
Clearly,
![NQ=NP+PQ=12+8=20](https://tex.z-dn.net/?f=NQ%3DNP%2BPQ%3D12%2B8%3D20)
. So, the first equation becomes
![NP=cNQ\iff12=20c\implies c=\dfrac{12}{20}=\dfrac35](https://tex.z-dn.net/?f=NP%3DcNQ%5Ciff12%3D20c%5Cimplies%20c%3D%5Cdfrac%7B12%7D%7B20%7D%3D%5Cdfrac35)
Then in the second equation, you have
Pls show what you need help with
Answer:
B) Positive liner association
Answer:
56 degrees
Step-by-step explanation:
Add 34 and 90 together
34 + 90 = 124
Subtract 180 by 124 = 56
If this answer is correct, please make me Brainliest!