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pickupchik [31]
3 years ago
7

Find the area of the polygon.A)125ftB)140ftC)165ftD)345ft

Mathematics
2 answers:
jek_recluse [69]3 years ago
8 0
Answer is C here is why hope. This helps
Bingel [31]3 years ago
5 0
The answer is c your welcome

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Graph x2 + 9y2 = 25. What are the domain and range?<br> Someone please help me !<br> (Picture below)
Dahasolnce [82]
The equation is equivalent to x2/25 + y2/(25/<span>9)</span>= 1, it is an ellipse equation 
the center is C(0,0)
                     a=5; b= 5/3, so a>b it is a horizontal major axis type (the x-axis)
all that you do is to find all characteristics by following all required formula
         
4 0
3 years ago
Given the zeros, write the polynomial. <br> x= -1, 1+3i
tresset_1 [31]

Answer:

I don't understand if i is a vraorable ro not

Step-by-step explanation:

5 0
3 years ago
Anyone wanna help me please
Art [367]

Answer:

the answer to this is x=16.1

8 0
3 years ago
Read 2 more answers
How do you solve 800m 35cm-154m 49cm for the smaller unit?
bearhunter [10]
1 m = 100 cm
800 m = 800 x 100 = 80000 cm
Therefore, 800 m 35 cm = 80000 cm + 35 cm = 80035 cm

Also, 154 m = 154 x 100 = 15400 cm
Therefore, 154 m 49 cm = 15449 cm

Therefore, <span>800m 35cm - 154m 49cm = 80035 cm - 15449 cm = 64586 cm = 645m 86cm</span>
4 0
3 years ago
Explain why the function is discontinuous at the given number
Blizzard [7]
For f to be continuous at x=5, we need to have

\displaystyle\lim_{x\to5}f(x)=f(5)

Note that x\to5 means that x\neq5, but that x is *approaching* 5. We're told that for x\neq5, we have

f(x)=\dfrac{x^2-5x}{x^2-25}

We can write

\dfrac{x^2-5x}{x^2-25}=\dfrac{x(x-5)}{(x+5)(x-5)}=\dfrac x{x+5}

and the limit would be

\displaystyle\lim_{x\to5}\frac x{x+5}=\dfrac5{5+5}=\dfrac5{10}=\dfrac12\neq1=f(5)

and so f is discontinuous.
5 0
3 years ago
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