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Irina-Kira [14]
3 years ago
5

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold.
5.Suppose Sal's total profit on lunch specials for the next month is $1,593. The profit amounts are the same: $2 for each sandwich and $3 for each wrap. In a paragraph of at least three complete sentences, explain how the graphs of the functions for the two months are similar and how they are different.
6.Below is a graph that represents the total profits for a third month. Write the equation of the line that represents this graph. Show your work or explain how you determined the equations.

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0





This is the graph in 'slope-intercept' form. From here it is easy to see that gradient  = and that y-intercept = 490.
The easiest way to draw a straight-line graph, such as this one, is to plot the y-intercept, in this case (0, 490), then plot another point either side of it at a fair distance (for example substitute  = -5 and  = 5 to procure two more sets of co-ordinates). These can be joined up with a straight line to form a section of the graph, which would otherwise extend infinitely either side - use the specified range in the question for x-values, and do not exceed it (clearly here the limit of -values is 0 ≤ x ≤ 735, since neither x nor y can be negative within the context of the question - the upper limit was found by substituting  = 0).
In function notation, the graph is:


The graph of this function represents how the value of the function varies as the value of x varies. Looking back at the question context, this graph specifically represents how many wraps could have been sold at each number of sandwich sales, in order to maintain the same profit of $1470.
When the profit is higher, the gradient is not changed (this is defined by the relationship between the $2 and $3 prices, not the overall profit) - instead the -intercept is higher:





Therefore we have gleaned that the new y-intercept is 531.
Clearly I cannot see the third straight line. However the method for finding the equation of a straight line graph is fairly simple:
1. Select two points on the line and write down their coordinates2. The gradient of the line = 3. Find the change in  (Δ4. Find the change in  (Δ5. Divide the result of stage 3 by the result of stage 46. This is your gradient7. Take one of your sets of coordinates, and arrange them in the form , where your  is the gradient you just calculated8. There is only one variable left, which is  (the y-intercept). Simply solve for this9. Now generalise the equation, in the form , by inputting your gradient and y-intercept whilst leaving the coordinates as  and 
For example if the two points were (1, 9) and (4, 6):
Δ = 6 - 9 = -3Δ = 4 - 1 = 3 =  = -1I choose the point (4, 6)6 = (-1 * 4) + c6 = c - 4c = 10Therefore, y=10-x

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Step-by-step explanation:

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If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
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Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

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