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Arisa [49]
4 years ago
15

Chen’s house is 53 years old. This is 5 more than twice the age of Sunny’s house, h.

Mathematics
1 answer:
tankabanditka [31]4 years ago
5 0

Answer:

The Equation which shows the equality is 53 = 2 h + 5 ,

The age of Sunny's house is 24 years old

Step-by-step explanation:

Given as ;

The age of the house of Chen's is 53 years old

Let the age of of the house of sunny = h years old

So, according to question

Chen's house age is 5 years more than twice the age of sunny's house

I.e Chen's house age = 2 × sunny's house age + 5

Or, 53 = 2 × h + 5

or,  2 × h = 53 - 5

so . 2 × h = 48

∴    h = \frac{48}{2} = 24 years

Hence The Equation which shows the equality is 53 = 2 h + 5 , And The age of Sunny's house is 24 years old .  Answer

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8 0
4 years ago
2c - 5 < -21 - 2c pls
Mars2501 [29]

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4 0
3 years ago
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
The two cross sections shown are taken parallel to their respective bases. The cross sections have the same area. If the heights
slavikrds [6]

Answer:

489.40 cm³

Step-by-step explanation:

Since the cross section is parallel to their respective bases, hence:

Area of the cylinder cross section = area of the circular base = πr²

where r is the radius of the cylinder base.

Area of other cross section = area of rectangle base = 3.8 cm * 8.1 cm

Since both cross sections have same area, hence:

Area of cylinder cross section = Area of rectangle base

πr² = 8.1 * 3.8

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8 0
3 years ago
Suppose a researcher is estimating the proportion of trees showing signs of disease in a local forest. They randomly sample 150
Serhud [2]

Answer:

0.167 - 1.96 \sqrt{\frac{0.167(1-0.167)}{150}}=0.107

0.167 + 1.96 \sqrt{\frac{0.167(1-0.167)}{150}}=0.227

And the 95% confidence interval would be given (0.107;0.227).

Step-by-step explanation:

Information given

X= 25 number of trees with signs of disease

n= 150 the sample selected

\hat p=\frac{25}{150}= 0.167 the proportion of trees with signs of disease

The confidence interval for the true proportion would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the significance is \alpha=1-0.95=0.05 and \alpha/2=0.025, and the critical value would be

z_{\alpha/2}=1.96

And replacing we got:

0.167 - 1.96 \sqrt{\frac{0.167(1-0.167)}{150}}=0.107

0.167 + 1.96 \sqrt{\frac{0.167(1-0.167)}{150}}=0.227

And the 95% confidence interval would be given (0.107;0.227).

6 0
3 years ago
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