Answer: The probability in (b) has higher probability than the probability in (a).
Explanation:
Since we're computing for the probability of the sample mean, we consider the z-score and the standard deviation of the sampling distribution. Recall that the standard deviation of the sampling distribution approximately the quotient of the population standard deviation and the square root of the sample size.
So, if the sample size higher, the standard deviation of the sampling distribution is lower. Since the sample size in (b) is higher, the standard deviation of the sampling distribution in (b) is lower.
Moreover, since the mean of the sampling distribution is the same as the population mean, the lower the standard deviation, the wider the range of z-scores. Because the standard deviation in (b) is lower, it has a wider range of z-scores.
Note that in a normal distribution, if the probability has wider range of z-scores, it has a higher probability. Therefore, the probability in (b) has higher probability than the probability in (a) because it has wider range of z-scores than the probability in (a).
Answer:
18√3
Step-by-step explanation:
tan Ф = opposite/adjacent
tanФ = AB/AC
tan 60 = AC/AB
Tan 60 =√3 AB=18
√3=AC/18
AC=18√3
Answer:
Answer 6.582
Step-by-step explanation:
0 6. 5 8 2
1 5 9 8. 7 3 0
− 0
9 8
− 9 0
8 7
− 7 5
1 2 3
− 1 2 0
3 0
− 3 0
0
Hope its understandable ._.
Answer:
There is no solution to the problem
Step-by-step explanation:
In order to find the solutions to the problem you can write the situation in an algebraic form.
You have that a number is equal to twice a smaller number plus 3. This can be written as follow:
(1)
where x is the number and y is the smaller number
Furthermore, the same number x is equal to twice the sum of the smaller number and 1, which can be written as follow:
(2)
To find the solution you equal the equation (1) with (2), and you solve for y:
You obtain an inconsistency, hence, the situation of the problem does not have solution
