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Whitepunk [10]
3 years ago
9

Is 12n2+12n+1 prime over the set of polynomials with rational coefficients? Need help ASAP

Mathematics
1 answer:
professor190 [17]3 years ago
8 0

Answer:

No, the given polynomial is not prime.

Step-by-step explanation:

Given: a polynomial 12n^2+12n+1

To check: whether the given polynomial is prime or not.

Solution:

A prime polynomial is a polynomial that cannot be factored into polynomials of lower degree and has integers as coefficients.

In the given polynomial, coefficients are integers.

Also, the polynomial 12n^2+12n+1 cannot be factored further into polynomials of lower degree.

So, the given polynomial is not prime.

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ANSWER ASAP!!! Find the length of the segment indicated
trapecia [35]

Answer:

14.45

Step-by-step explanation:

x^2+(7.1)^2=(16.1)^2

×^2+50.41=259.21

x^2=208.8

sqrt(x^2)=sqrt(208.8)

x=14.45

check.

14.45^2 + 7.1^2 = 16.1^2

4 0
3 years ago
What is the minimum number of feet you should be to avoid being electrocuted by overhead power lines up to 50kV? A. 10 feet B. 1
Andrei [34K]

Answer:

I believe the answer is A 10 feet

Step-by-step explanation:


4 0
3 years ago
Im having trouble finding facts that are in scientific notation. a good example is: a microbe is 1.23*10^-3 small. (this is not
Afina-wow [57]
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4 0
3 years ago
Read 2 more answers
For students who first enrolled in two year public institutions in a recent​ semester, the proportion who earned a​ bachelor's d
kondaur [170]

Answer:

Null hypothesis =  H_0:p=0.395

Alternate hypothesis =H_a:p>0.395

Step-by-step explanation:

Given : In a recent​ semester, the proportion who earned a​ bachelor's degree within six years was 0.395.

The president of a certain college believes that the proportion of students who enroll in her institution have a higher completion rate.

To Find : Determine the null and alternative hypotheses.

Solution:

In a recent​ semester, the proportion who earned a​ bachelor's degree within six years was<u> 0.395. </u>

Claim : the proportion of students who enroll in her institution <u>have a higher completion rate.</u>

So,null hypothesis =  H_0:p=0.395

Alternate hypothesis =H_a:p>0.395

6 0
3 years ago
Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = ln x, [1,7] choose one letter t
inn [45]
ANSWER

B.Yes, f is continuous on [1, 7] and differentiable on (1, 7).

c\approx 3.08

EXPLANATION

The given

f(x) = ln(x)

The hypotheses are

1. The function is continuous on [1, 7].

2. The function is differentiable on (1, 7).

3. There is a c, such that:

f'(c) = \frac{f(7) - f(1)}{7 - 1}

f'(x) = \frac{1}{x}

This implies that;

\frac{1}{c} = \frac{ ln(7) - 0}{6}

\frac{1}{c} = \frac{ ln(7)}{6}

c = \frac{6}{ ln(7) }

c\approx 3.08

Since the function is continuous on [1, 7] and differentiable on (1, 7) it satisfies the mean value theorem.
7 0
3 years ago
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