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ludmilkaskok [199]
3 years ago
10

Find each difference. Write in simplest form. 3 4/6 - 1 5/6=

Mathematics
2 answers:
kodGreya [7K]3 years ago
4 0

Answer:

1 5/6

Step-by-step explanation:

Turn the mixed fractions into improper fractions

3 4/6 = 22/6 and 1 5/6 = 11/6

Do the subtraction

22/6 - 11/6 = 11/6 or 1 5/6.

natulia [17]3 years ago
3 0

Answer:2 1/6

I got this because you minus the whole number which I got 2. Then 5/6 - 4/6 is 1/6 because they are common demonstrates so I did 5-4 and got 1 then I added the six and got 1/6

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The local swim team is considering offering a new semi-private class aimed at entry-level swimmers, but needs a minimum number o
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Answer:

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

Step-by-step explanation:

For this case we define the random variable X as the number of entry-level swimmers and we are interested about the true population mean for this variable . On specific we want to test this:

Null hypothesis: \mu \leq 15

Alternative hypothesis: \mu > 15

And the statistic is given by:

z =\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

The significance level is \alpha=0.01 and since we are conducting a right tailed test we need to find a critical value who accumulate 0.01 of the area in the right of the normal standard distribution and we got:

z_{\alpha/2}= 2.326

So we reject the null hypothesis is z>2.326

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3 years ago
What are the coordinates of the vertex of the parabola described by the
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Answer: D. ( -7, - 2 )

Step-by-step explanation:

Rewrite this in vertex form and use this to find the vertex. ( h, k )

8 0
3 years ago
Read 2 more answers
What are all the common factors of 36 and 56? A. 1, 2, 4 B. 1, 2 C. 1, 2, 3, 4, 9 D. 1, 2, 4, 8
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I think the answer is A.1,2,4
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3 years ago
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Sarah wants to arrive at her friend's wedding at 3:00. The distance from Sarah's house to the wedding is 97 miles. Based on usua
atroni [7]

Answer:

First, you need to remember the relation:

speed = distance/time

We know that she needs to arrive at her friend's wedding at 3:00.

We also know that the total distance between her house and the wedding is 97 miles.

Now we need to find the total time that she needs to arrive at the wedding, so we can estimate at which hour she needs to start the travel.

The first 20 miles are driven att 30 miles per hour.

Then:

distance = 20mi

speed = 30mi/h

30mi/h = 20mi/T

T = 20mi/(30mi/h) = 0.67 hours.

The next 12 miles are driven at 45 mi/h

then:

45mi/h = 12mi/T

T = (12mi/(45mi/h)) = 0.27 hours

And the remainder distance is traveled at 65 mi/h

First, at this point she did travel 20mi + 12mi = 32mi

And we know that the total distance was 97mi, then the remaining distance is:

97mi - 32mi = 65mi

Then now she travels 65 miles at the speed of 65mi/h

then:

65mi/h = 65mi/(T)

T = (65mi)/(65mi/h) = 1 hour

Then the total time needed for the travel is:

Time =  0.67 hours + 0.27 hours + 1 hour = 1.94 hours.

knowing that 1 hour = 60 min

0.94 hours = 0.94*(60 min) = 56.4 min

time = 1 hour and 56.4 min

Meaning that she needs to leave her house around two hours before 3:00

So she would need to leave her house at around 1:03

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3 years ago
............................
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3.81 Divide the mass value by 2.205
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