The probability would be 39.9%
The given probability states that 39.9% of the 3 years olds are in daycare. Therefore, it would be obvious to assume that if you randomly selected a 3 year old, that would be the probability that he/she is in daycare.
Answer: x = -0.377
Step-by-step explanation:
We have the equation:
4^(5*x) = 3^(x - 2)
Now we can use the fact that:
Ln(A^x) = x*Ln(A)
Then we can apply Ln(.) to both sides of the equation to get:
Ln(4^(5*x)) = Ln(3^(x - 2))
(5*x)*Ln(4) = (x - 2)*Ln(3)
(5*x)*Ln(4) - x*Ln(3) = -2*Ln(3)
x*(5*Ln(4) - Ln(3)) = -2*Ln(3)
x = -2*Ln(3)/(5*Ln(4) - Ln(3)) = -0.377
OPTION:
B
Step-by-step explanation:
-2/3x + 2.8 = -8.2 what is x
Add 2.8 on both side of the equation
-2/3x=-11
Divide both side by -2/3
x=33/2
Check: -2/3(33/2)+ 2.8 = -8.2
-11+2.8=-8.2
-8.2=-8.2
Answer is x=33/2
