Answer:
Mark C.
Step-by-step explanation:
If there are 27 students in both classes, it's logicial to multiply both classes by two to get the total students.
Since the <em>S</em> stands for the students absent, that should come after the brackets.
4114.5 Balance method used
1.4=h/5
multiply both sides by 5
h=7
Let
x--------> the length side of the rectangle
y--------> the width side of the rectangle
we know that
The perimeter of a rectangle is equal to



Substitute the values of x and y in the formula of perimeter
![P=2*[(4a + 96)/(a + 15)]+2*[(4a + 24)/(a + 15)]](https://tex.z-dn.net/?f=%20P%3D2%2A%5B%284a%20%2B%2096%29%2F%28a%20%2B%2015%29%5D%2B2%2A%5B%284a%20%2B%2024%29%2F%28a%20%2B%2015%29%5D%20)
![P=[(8a + 192)/(a + 15)]+[(8a + 48)/(a + 15)]](https://tex.z-dn.net/?f=%20P%3D%5B%288a%20%2B%20192%29%2F%28a%20%2B%2015%29%5D%2B%5B%288a%20%2B%2048%29%2F%28a%20%2B%2015%29%5D%20)
![P=[(16a + 240)/(a + 15)]](https://tex.z-dn.net/?f=%20P%3D%5B%2816a%20%2B%20240%29%2F%28a%20%2B%2015%29%5D%20)
![P=16*[(a + 15)/(a + 15)]](https://tex.z-dn.net/?f=%20P%3D16%2A%5B%28a%20%2B%2015%29%2F%28a%20%2B%2015%29%5D%20)

therefore
<u>the answer part a) is </u>
the total length of fencing material required would be 
Part b) Divide the perimeter by the width of the prebuilt fence sections
so

therefore
<u>the answer Part b) is </u>
