Answer:
15°.
Step-by-step explanation:
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Have a good Day!
GIVE BRANLIEST LOOK AT IMAGE THE ANSWER IS ON THAT IMAGE TRUST ME
Step-by-step explanation:
x y
1 16
2 12
3 8
5 0
Step-by-step explanation:
you have to substitute ever number on the X side in the equation to get the Y
for example 1 is under x so you will take
y=20-4(1)
y=20-4
y=16
The area of a circle is \pi r^2, where r is the radius of the circle. The diameter of a circle is the length of a line that passes through the center of the circle and stops at the perimeter of circle. The radius of a circle is half the diameter. Divide the diameter by 2 to find the radius.
1. 2.8 m / 2 = 1.4 m
2 .

: Plug in the value we just found for r.
3.

: Use the order of operations (PEMDAS).
4.

The area of the circle is equal to