Rearrange (∛7ab²)³ to have a rational exponent.

How to do this. Can you maybe show me your work?

Musya8 [376]

VX = 204
Divide by 3 to get the 2/3 , 1/3 ratio of the segments
204/3= 68
68*2= 136
VW= 136, XW= 68
Do the same for RW, RY
RW= 104 this is 2/3 of the segment. Divide by 2.
WY= 52. RY= 156

#7
Find the midpoint of each side. (0,2) (7,4) m1=(3.5,3)
(0,3) (5,0) m2=(2.5,1.5)
(5,0) (7,4) m3=(6,2)
Draw a segment from each midpoint to its opposite vertex. The point of intersection is (4,2)

7 0

3 years ago

Hi, I need help with all of these questions! (screenshots included) Thank you! I really appreciate it.

klemol [59]

Answer:

I'm unsure about the first one, but the second one is irrational, the third one is option C, the fourth is option b, and the last one is D i believe

Step-by-step explanation:

4 0

3 years ago

Determine the most precise name for ABCD (parallelogram, rhombus, rectangle, or square). Explain how you determined your answer.

Sonja [21]

<h3>Answer: Rhombus</h3>

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Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\$

Segment AB is exactly $\sqrt{17}$ units long, which is approximately 4.1231 units.

If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

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Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

$A = (x_1,y_1) = (3,5) \text{ and } B = (x_2,y_2) = (7,6)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{6 - 5}{7 - 3}\\\\m = \frac{1}{4}\\\\$

Segment AB has a slope of 1/4.

Do the same for BC

$B = (x_1,y_1) = (7,6) \text{ and } C = (x_2,y_2) = (6,2)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{2 - 6}{6 - 7}\\\\m = \frac{-4}{-1}\\\\m = 4\\\\$

Unfortunately the two slopes of 1/4 and 4 are not negative reciprocals of one another. One slope has to be negative while the other is positive, if we wanted perpendicular lines. Also recall that perpendicular slopes must multiply to -1.

We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.