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Leokris [45]
3 years ago
8

a drawing of a surboard in a catalog shows it's length as 8 4/9 inches. find the actual length of surfboard if 1/2 inch length o

n the drawing correspond to 3/8 foot of actual length.
Mathematics
1 answer:
Delvig [45]3 years ago
8 0
\frac12 in -\frac38 ft \\
8\frac48 in - x\ ft\\
\\
\frac12x=\frac38 \cdot 8\frac49\\
\frac12x=\frac38 \cdot \frac{76}9\\
\frac12x=\frac{76}{24}\ /\cdot 2\\
x=\frac{76}{12}=6\frac13 ft\\\\
Answer:Actual\ lenght\ is\ 6\frac13ft.
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Correct question is;

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Answer:

A)UCL = 466

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B)UCL = 462

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Step-by-step explanation:

We are given;

Mean;μ = 450

Standard deviation; σ = 20

Sample size; n = 25

A) We are told that these limits are chosen to be four standard deviations from the target.. This means that z-value = 4.

Thus, upper control limit will be the formula;

UCL = μ + 4σ/√n

UCL = 450 + 4(20)/√25

UCL = 450 + 16

UCL = 466

Lower control limit will be;

LCL = μ - 4σ/√n

LCL = 450 - 4(20)/√25

LCL = 450 - 16

LCL = 434

B) We are now told that these limits are chosen to be three standard deviations from the target.

Thus, z = 3

So;

UCL = μ + 3σ/√n

UCL = 450 + 3(20)/√25

UCL = 450 + 12

UCL = 462

Lower control limit will be;

LCL = μ - 3σ/√n

LCL = 450 - 3(20)/√25

LCL = 450 - 12

LCL = 438

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