Two boats start their journey from the same point A and travel along directions AC and AD, as shown below:

Please help! Do you know the answer<br>

azamat

Answer:

x = 9

Step-by-step explanation:

y = 2/3x - 6

If the y point is 0, then plug that number into the equation and solve for x.

0 = 2/3x - 6

Add 6 to both sides of the equation.

6 + 0 = 2/3x - 6 + 6 or 6 = 2/3x

Multiply both sides by 3.

3 x 6 = 2/3x x 3 or 18 = 2x

Divide both sides by 2

18/2 = 2x / 2 or 9 = x

5 0

3 years ago

I don't understand what to do because I don't understand the question

kirill [66]

Find the 2 different rates at which the farm worker worked:

3 pints
--------- = 0.75 pint/min
4 min

2 pints
---------- = 0.67 pint/ min
3 min

Then you need to subtract 0.67 pint/min from 0.75 pint/min to answer this question.

Alternatively, subtract 2/3 pint/min from 3/4 pint/min.

4 0

3 years ago

Cos ( α ) = √ 6/ 6 and sin ( β ) = √ 2/4 . Find tan ( α − β )

Zina [86]

Answer:

$\purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

Step-by-step explanation:

$\cos( \alpha ) = \frac{ \sqrt{6} }{6} = \frac{1}{ \sqrt{6} } \\ \\ \therefore \: \sin( \alpha ) = \sqrt{1 - { \cos}^{2} ( \alpha ) } \\ \\ = \sqrt{1 - \bigg( {\frac{1}{ \sqrt{6} } \bigg )}^{2} } \\ \\ = \sqrt{1 - {\frac{1}{ {6} }}} \\ \\ = \sqrt{ {\frac{6 - 1}{ {6} }}} \\ \\ \red{\sin( \alpha ) = \sqrt{ { \frac{5}{ {6} }}} } \\ \\ \tan( \alpha ) = \frac{\sin( \alpha ) }{\cos( \alpha ) } = \sqrt{5} \\ \\ \sin( \beta ) = \frac{ \sqrt{2} }{4} \\ \\ \implies \: \cos( \beta ) = \sqrt{ \frac{7}{8} } \\ \\ \tan( \beta ) = \frac{\sin( \beta ) }{\cos( \beta ) } = \frac{1}{ \sqrt{7} } \\ \\ \tan( \alpha - \beta ) = \frac{ \tan \alpha - \tan \beta }{1 + \tan \alpha . \tan \beta} \\ \\ = \frac{ \sqrt{5} - \frac{1}{ \sqrt{7} } }{1 + \sqrt{5} . \frac{1}{ \sqrt{7} } } \\ \\ = \frac{ \sqrt{35} - 1 }{ \sqrt{7} + \sqrt{5} } \\ \\ \purple{ \bold{ \tan( \alpha - \beta ) = 1.00701798}}$

8 0

3 years ago

Consider a continuous random variable x, which is uniformly distributed between 65 and 85. The probability of x taking on a valu

madam [21]

We will see that the probability of x taking on a value between 75 to 90 is P = 0.5

<h3>How to get the probability?</h3>

We know that x is a continuous random variable uniformly distributed between 65 and 85.

This means that the probability that x value y in the range is such that:

1 = P(y)*(85 - 65) = P(y)*20

1/20 = P(y).

Now, the probability of x taking a value between 75 and 85 is:

P(75 to 85) = (1/20)*(85 - 75) = 10/20 = 0.5

And the probability between 85 and 90 is zero (because the maximum value that x can take is 85, so this part does not affect).

Then we conclude that the probability of x taking a value between 75 to 90 is:

P(75 to 90) = P(75 to 85) + P(85 to 90) = 0.5 + 0 = 0.5

If you want to learn more about probability, you can read:

brainly.com/question/251701

5 0

1 year ago

In a small town, the stray cat population is rapidly increasing. There are currently 20 stray cats, and it is estimated

BigorU [14]

2 years will be 80 cats (20 x 2 = 40 (year 1) and 40 x 2 = 80 (year 2))

3 years will be 160 (80 x 2 = 160)

5 years will be (160 x 2 = 320 (year 4) and 320 x 2 = 640 (year 5)) So 5 years will be 640

7 0

3 years ago