Answer:
yes,this is congruent by SAS criteria
Answer:
There were 6 benches in park 1 and 18 benches in park 2.
Step-by-step explanation:
Let x be the no of benches in Park 1 and y in park 2.
Given that there are 12 more benches in park 2 than 1
Writing this in equation form, we have y = x+12 ... i
Next is if 2 benches were transferred from park 2 to park 1, then we have
x+2 in park 1 and y-2 in park 2.
Given that y-2 = twice that of x+2
Or y-2 = 2x+4 ... ii
Rewrite by adding 2 to both sides of equation ii.
y = 2x+6 ... iii
i-iii gives 0 = -x+6
Or x =6
Substitute in i, to have y = 6+12 = 18
Verify:
Original benches 6 and 18.
18 = 6+12 hence I condition is satisfied
18-2 = 2(6+2)
II is also satisfied.
Answer: D
Step-by-step explanation:
A) 3*0^2+2(0-5)>8
-10>8 -> not true
B) 3*(-1)^2+2(-1-5)>8
3*1+2*(-6)>8
3- 12>8
-9> 8 -> not true
C) 3*(-2)^2+2(-2-5)>8
3*4+2*(-7)>8
12-14>8
-2> 8 -> not true
D) ) 3*(-3)^2+2(-3-5)>8
3*9+2*(-8)>8
27-16>8
11> 8 -> true
[x-(-10)]²+(y-6)²=4²
the answer is (<span>x + 10)^2 + (y – 6)^2 = 16</span>
