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ExtremeBDS [4]
3 years ago
7

M is the midpoint of line segment AB. If the coordinates of M are (2, 6) and the coordinates of B are (5, 10), which of the foll

owing represents the coordinates of point A?
Mathematics
1 answer:
Nitella [24]3 years ago
8 0

Answer:

The coordinates are A(-1,2)

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

In this problem we have

M(2,6)\\A(x_1,y_1)

B(x_2,y_2) ---> B(5,10)

substitute the given values

(2,6)=(\frac{x_1+5}{2},\frac{y_1+10}{2})

Solve for x_1

2=(x_1+5)/2\\4=x_1+5\\x_1=4-5=-1

Solve for y_1

6=(y_1+10)/2\\12=y_1+10\\y_1=12-10=2

therefore

The coordinates are A(-1,2)

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A loan processing office receives 4 loan requests every hour. The office has 2 departments. It takes the first department on ave
jenyasd209 [6]

Answer:

On average how many requests are in the first department (including those who are waiting) is 1.32.

Step-by-step explanation:

In this case, use the Little's law of queuing theory.

The Little's law states that the average number of customers in a fixed system (L) is equal to the average effective arrival rate (λ) multiplied by the average time a customer spends in the system (W).

The number of requests per hour in the 1st department is, λ₁ = 4.

It is provided that 20% are rejected directly by the 1st department without going into the 2nd department.

Then the number of requests per hour is, λ₂ = 4\times 80\%=4\times0.80=3.2

The average time a customer spends in the 1st department,

W₁ = 20 minutes = 0.33 hours.

The average time a customer spends in the 1st department,

W₂ = 60 minutes = 1 hour

On average how many requests are in the first department (including those who are waiting) is:

<em>L</em> = λ₁ × W₁

  = 4 × 0.33

  = 1.32

Thus, on average how many requests are in the first department (including those who are waiting) is 1.32.

6 0
4 years ago
An element with a mass 310 grams decays by 5.7% per minute. How much of the element is remaining after 9 minutes, to the nearest
balu736 [363]

Mass of an element = 310 grams

Percentage of the element that will decay in a minute = 5.7%

Quantity of the element that will decay in one minute :

=  \frac{5.7 \times 310}{100}

=  \frac{1767}{100}

= \tt17.67 \: grams

Thus, 17.67 grams of the element will decay every minute.

Quantity of element that will decay after nine minutes :

= 17.67 \times 9

=\tt 159.03 \: grams

Thus, 159.03 grams of the element will decay after 9 minutes.

Quantity of element that will remain after 9 minutes :

= 310 - 159.03

= \tt150.97 \: grams

Thus, 150.97 grams of the element will remain after nine minutes.

We can round off 150.97 to 151.00.

Therefore, <u>151.00 grams</u> of the element will remain after 9 minutes.

6 0
3 years ago
What is x= when the equation is 3x-1=8-3x
aleksley [76]
3x-1=8-3x \\\\ 3x+3x=8+1 \\\\ 6x=9 \\\\ \boxed{x=\frac{9}{6}=\frac{3}{2}}
4 0
3 years ago
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kolbaska11 [484]
9/8 would be the fraction.
7 0
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Which equation is quadratic in form?
Helga [31]

Answer: Option 1 is correct.

Step-by-step explanation:

As we know that the quadratic form needs the highest degree to be '2' only.

So,

In Option 1, we have ,

2(x+5)^2+8x+5+6=0\\\\2(x^2+10x+25)+8x+11=0\\\\2x^2+20x+50+8x+11=0\\\\2x^2+28x+61=0\\\\\text{ Hence , it is the required quadratic form. }

Hence, Option 1 is correct.

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