Sixtoadnhsjakndkjsabdhkasb dnaskjdbnaksjd ka d sakd aks d.ljsk aldlas ld aslad
The same constant value(s)
coordinate of B= (2+3,0) = (5,0)
by pythagoras' theorem,
height of triangle^2 + half length of AB^2 = AC^2
height of triangle^2 = 3^2-1.5^2
height of triangle ^2= 6.75
height of triangle= √6.75
coordinates of C= (1.5,√6.75)
