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uranmaximum [27]

3 years ago

14

Suppose the skater loses the function of one of their body systems. Can the skater continue to skate with a body system that is

not functioning properly

1 answer:

Iteru [2.4K]3 years ago

4 0

Answer:

No, the skater cannot

Step-by-step explanation:

Base on the scenario been described in the question, we can see that the skater loses what part of his body which he use for the sporting activities of skating, unfortunately he loses it, so he cannot be able to continue skating. Because his body system will not function properly

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Anita sells her ring at the price of Rp 540,000.00. If Anita gets If Anita gets the profit of 20%, then how much does Anita buy

vagabundo [1.1K]

Answer:

selling price=Rp 540,000.00.

profit=20%

cost price=selling price- profit% of cost price

cost price+profit% of cost price=selling price

cost price (1+20%)=Rp 540,000.00.

cost price=Rp 540,000.00./(1+20/100)=Rp 450000.00 is your answer

5 0

3 years ago

141.1933-67.53 =<br> (Divided, not minus)

Sphinxa [80]

Answer: I think its 2.09

Step-by-step explanation:

But i'm not sure.

5 0

3 years ago

In ΔABC, AB = 16 in, BC = 9 in, AC = 10 in. AD is perpendicular to the extension of BC . Find CD.

ollegr [7]

Answer:

25/6

I don't really know how I got it, sorry I can't help with that

4 0

3 years ago

Use the method of variation of parameters to find a particular solution of the given differential equation. Then check your answ

olga_2 [115]

Answer:

Therefore the complete primitive is

$y=c_1 e^{2y}+c_2e^{3t}+e^{t}$

Therefore the general solution is

$y=c_1e^{2t}+c_2e^{3t}+e^t$

Step-by-step explanation:

Given Differential equation is

$y''-5y'+6y=2e^t$

<h3>Method of variation of parameters:</h3>

Let $y=e^{mt}$ be a trial solution.

$y'= me^{mt}$

and $y''= m^2e^{mt}$

Then the auxiliary equation is

$m^2e^{mt}-5me^{mt}+6e^{mt}=0$

$\Rightarrow m^2-5m+6=0$

$\Rightarrow m^2 -3m -2m +6=0$

$\Rightarrow m(m -3) -2(m -3)=0$

$\Rightarrow (m-3)(m-2)=0$

$\Rightarrow m=2,3$

∴The complementary function is $C_1e^{2t}+C_2e^{3t}$

To find P.I

First we show that $e^{2t}$ and $e^{3t}$ are linearly independent solution.

Let $y_1=e^{2t}$ and $y_2= e^{3t}$

The Wronskian of $y_1$ and $y_2$ is $\left|\begin{array}{cc}y_1&y_2\\y'_1&y'_2\end{array}\right|$

$=\left|\begin{array}{cc}e^{2t}&e^{3t}\\2e^{2t}&3e^{3t}\end{array}\right|$

$=e^{2t}.3e^{3t}-e^{2t}.2e^{3t}$

$=e^{5t}$ ≠ 0

∴ $y_1$ and $y_2$ are linearly independent.

Let the particular solution is

$y_p=v_1(t)e^{2t}+v_2(t)e^{3t}$

Then,

$Dy_p= 2v_1(t)e^{2t}+v'_1(t)e^{2t}+3v_2(t)e^{3t}+v'_2(t)e^{3t}$

Choose $v_1(t)$ and $v_2(t)$ such that

$v'_1(t)e^{2t}+v'_2(t)e^{3t}=0$ .......(1)

So that

$Dy_p= 2v_1(t)e^{2t}+3v_2(t)e^{3t}$

$D^2y_p= 4v_1(t)e^{2t}+9v_2(t)e^{3t}+ 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}$

Now

$4v_1(t)e^{2t}+9v_2(t)e^{3t}+ 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}-5[2v_1(t)e^{2t}+3v_2(t)e^{3t}] +6[v_1e^{2t}+v_2e^{3t}]=2e^t$

$\Rightarrow 2v'_1(t)e^{2t}+3v'_2(t)e^{3t}=2e^t$ .......(2)

Solving (1) and (2) we get

$v'_2=2 e^{-2t}$ and $v'_1(t)=-2e^{-t}$

Hence

$v_1(t)=\int (-2e^{-t}) dt=2e^{-t}$

and $v_2=\int 2e^{-2t}dt =-e^{-2t}$

Therefore $y_p=(2e^{-t}) e^{2t}-e^{-2t}.e^{3t}$

$=2e^t-e^t$

$=e^t$

Therefore the complete primitive is

$y=c_1 e^{2y}+c_2e^{3t}+ e^{t}$

<h3>Undermined coefficients:</h3>

∴The complementary function is $C_1e^{2t}+C_2e^{3t}$

The particular solution is $y_p=Ae^t$

Then,

$Dy_p= Ae^t$ and $D^2y_p=Ae^t$

$\therefore Ae^t-5Ae^t+6Ae^t=2e^t$

$\Rightarrow 2Ae^t=2e^t$

$\Rightarrow A=1$

$\therefore y_p=e^t$

Therefore the general solution is

$y=c_1e^{2t}+c_2e^{3t}+e^t$

4 0

3 years ago

In a recent census, New York City had a population of 8,336,697 people, and an area of 302.64 square miles, while London had a p

hichkok12 [17]

8,336,697 / 302.64 = <span>27547 (approximately)
The population density to the nearest person of NYC is 27,547 people per square mile.

3,792,621 / 469 = </span><span>8087 (approximately)
</span>The population density to the nearest person of London is 8,087 people per square mile.

5 0

4 years ago

Read 2 more answers