Answer:
B) car B
explanation :
I know that Car A can go at least 28 more miles than Car B. If you round 10.5 to the nearest ones place it would be 11; and if you round 12.5 to the nearest ones place it would be 13 so 13 - 11 = 2
I hope I can help you have a great day :)
Answer:
33 meters
51 meters
Step-by-step explanation:
84-18= 66
66/2= 33
33+18= 51
Check your answer:
51+33=84
Answer:
33
Step-by-step explanation:
If m = Mother's age and d = daughter's age, we can make the following equations
m = 3d
m + d = 44
Now, using substitution, we can substitute m for 3d in the second equation:
3d + d = 44, 4d = 44, d = 11
Then, we can plug d into the first equation: m = 3(11) = 33
Let's solve the equation 2k^2 = 9 + 3k
First, subtract each side by (9+3k) to get 0 on the right side of the equation
2k^2 = 9 + 3k
2k^2 - (9+3k) = 9+3k - (9+3k)
2k^2 - 9 - 3k = 9 + 3k - 9 - 3k
2k^2 - 3k - 9 = 0
As you see, we got a quadratic equation of general form ax^2 + bx + c, in which a = 2, b= -3, and c = -9.
Δ = b^2 - 4ac
Δ = (-3)^2 - 4 (2)(-9)
Δ<u /> = 9 + 72
Δ<u /> = 81
Δ<u />>0 so the equation got 2 real solutions:
k = (-b + √Δ)/2a = (-(-3) + √<u />81) / 2*2 = (3+9)/4 = 12/4 = 3
AND
k = (-b -√Δ)/2a = (-(-3) - √<u />81)/2*2 = (3-9)/4 = -6/4 = -3/2
So the solutions to 2k^2 = 9+3k are k=3 and k=-3/2
A rational number is either an integer number, or a decimal number that got a definitive number of digits after the decimal point.
3 is an integer number, so it's rational.
-3/2 = -1.5, and -1.5 got a definitive number of digit after the decimal point, so it's rational.
So 2k^2 = 9 + 3k have two rational solutions (Option B).
Hope this Helps! :)
Answer:
n = 19.89694
Step-by-step explanation:
You can work the problem using decimal numbers. There is no need to convert everything to integers. Trying to do so just gets you in trouble.
Subtract 2.2 from both sides:
-1.398 -2.200 = n/-5.53
-3.598 = n/-5.53
Now, multiply both sides by -5.53:
(-5.53)(-3.598) = n = 19.89694
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The one rule that cannot be violated in algebra is that <em>you must do the same thing to both sides of the equation</em>.
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Your "solution" so far has a couple of errors. The first is that you have apparently multiplied all of the numbers by 1000. Unfortunately, when you multiply a denominator by 1000, it is the same as dividing by 1000. So, you have multiplied the left side by 1000, multiplied one term on the right by 1000 and divided another term on the right by 1000. This turns the equation into something different than what you started with, and will give a wrong answer.
The second error is that you have subtracted 2200 only from the right side. This, too, will turn the equation into something different than what you started with, and will give a wrong answer.
