Is x+2 a factor of 3x^4+7x^3+3x^2-x-4?

1 answer:

4 0

Lets check by putting x= - 2
3x^4+7x^3+3x^2-x-4=0
3(-2)^4+7(-2)^3+3(-2)^2+2-4=0
3*16-56+12-2=0
48-56+10=
2=0 No
x+2 is not a factor

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Occasionally an airline will lose a bag. Suppose a small airline has found it can reasonably model the number of bags lost each

julia-pushkina [17]

Answer:

a) The probability that the airline will lose no bags next monday is 0.1108

b) The probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227

c) I would recommend taking a Poisson model with mean 4.4 instead of a Poisson model with mean 2.2

Step-by-step explanation:

The probability mass function of X, for which we denote the amount of bags lost next monday is given by this formula

$P(X=k) = \frac{e^{-2.2} * {2.2}^k }{k!}$

$P(X=0) = \frac{e^{-2.2} * {2.2}^0 }{0!} = 0.1108$

The probability that the airline will lose no bags next monday is 0.1108.

b) Note that $P(X \in \{0,1,2\} = P(X=0) + P(X=1) + P(X=2)$ . And

$P(X=0)+P(X=1)+P(X=2) = e^{-2.2} * (1 + 2.2 + 2.2^2/2) = 0.6227$

Therefore, the probability that the airline will lose 0,1, or 2 bags next Monday is 0.6227.

c) If the double of flights are taken, then you at least should expect to loose a similar proportion in bags, because you will have more chances for a bag to be lost. WIth this in mind, we can correctly think that the average amount of bags that will be lost each day will double. Thus, i would double the mean of the Poisson model, in other words, i would take a Poisson model with mean 4.4, instead of 2.2.

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2 years ago

Work out the answers to:

const2013 [10]

Answer:

A=-4 B=-8 C=8

Step-by-step explanation:

If you need to check these answers multiply the answer by the second number.

A) -4x-3=12 A negative times a negative is always positive.

B)-8x9=-72 A negative times a positive is a negative.

C) 8x-2=-16 A negative times a positive is a negative.

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