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hram777 [196]
3 years ago
7

How would i answer and show work for 4[5(12+3)-2]-7

Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0
4 [5(12+3)-2]-7
4 [5 (15)-2]-7
4 [75-2]-7
4 [73] -7
292-7
285

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the 43rd term of an arithmetic sequence is -671 and the 52nd term is -806. find the first term and the common difference.
Bond [772]

Answer:

First term = -41.

Common difference = -15.

Step-by-step explanation:

nth term: an = a1 + (n - 1)d  where a = first term and d = the common difference.

-671 = a1 + (43 - 1)d

-806 = a1 +(52 - 1)d

-671  = a1 + 42d

-806 = a1 + 51d

Subtracting ( to eliminate a1):

-671 - (-806) = 42d - 51d

-9d =  135

d = -15

Substitute for d in the first equation:

-671 = a1 + 42*-15

-671 = a1 - 630

a1 = -671 + 630 = -41.

3 0
3 years ago
7x to the power of 2 is a what is it<br>a) monomial<br>b) binomial<br>c) Trinomial​
Sedaia [141]
You can use the prefixes to figure this out:
Mono: one
Bi: two
Tri: three

So, because there is only one term, it is a monomial.
4 0
3 years ago
A company deposits $5,000 into an account that earns interest. The rate at which the value changes is given by dA/dt=0.0225A, wh
xxMikexx [17]

Answer:

  $6261.61

Step-by-step explanation:

The solution to the differential equation is the exponential function ...

  A(t) = 5000e^(0.0225t)

We want the account value after 10 years:

  A(10) = 5000e^(0.225) = 6261.61

The value of the account after 10 years will be $6,261.61.

_____

The rate of change equation basically tells you that interest is compounded continuously. After working interest problems for a while you know the formula for that is the exponential formula A = A0·e^(rt).

Or, you can solve the differential equation using separation of variables:

  dA/A = 0.0225dt

  ln(A) = 0.0225t +C . . . . integrate

  A(t) = A0·e^(0.0225t) = 5000·e^(0.0225t) . . . . solution for A(0) = 5000

7 0
3 years ago
A new sports car costs $21,000 at the dealership. If the dealership is
Molodets [167]

Answer:

16,800 dollars

Step-by-step explanation:

1. find 20 percent of 21,000= 4,200

2. subtract 4,200 from 21,000

21,000

-4,200

16,800 dollars

5 0
3 years ago
In 1995, the moose population in a park was measured to be 4200. By 1998, the population was measured again to be 1600. If the p
Contact [7]

Answer:

P = -2600/3 t + 25600/3

P = -8200/3

Step-by-step explanation:

t is the time in years since 1990, so two points on the line are (5, 4200) and (8, 1600).

Using the points to find the slope:

m = (y₂ − y₁) / (x₂ − x₁)

m = (1600 − 4200) / (8 − 5)

m = -2600/3

Now writing the equation in point-slope form:

P − 4200 = -2600/3 (t − 5)

Converting to slope-intercept form:

P − 4200 = -2600/3 t + 13000/3

P = -2600/3 t + 25600/3

In 2003, t = 13:

P = -2600/3 (13) + 25600/3

P = -8200/3

6 0
3 years ago
Read 2 more answers
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