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Harman [31]
3 years ago
10

TEN POINTS:

Mathematics
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

81/16 = 5 1/16

Step-by-step explanation:

-4(square root of x) -3 = -12

Add 3 to both sides

-4(square root of x) = -12 +3 = -9

Divide both sides by -4

(square root of x) = -9/-4

-/- equals +

(square root of x) = 9/4

Square both sides to cancel the square root

x = (9/4)^2 = 81/16 = 5 1/16

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Let f(x) be a continuous function such that f(1) = 3 and f '(x) = sqrt( x^3 + 4 ). What is the value of f(5)?
snow_lady [41]

The value of f(5) is 49.1

Step-by-step explanation:

To find f(x) from f'(x) use the integration

f(x) = ∫ f'(x)

1. Find The integration of f'(x) with the constant term

2. Substitute x by 1 and f(x) by π to find the constant term

3. Write the differential function f(x) and substitute x by 5 to find f(5)

∵ f'(x) =  + 6

- Change the root to fraction power

∵  =

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∴ f(x) = ∫  + 6

- In integration add the power by 1 and divide the coefficient by the

 new power and insert x with the constant term

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- c is the constant of integration

∵

∴ f(x) =   + 6x + c

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- Subtract 6.4 from both sides

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To find f(5) Substitute x by 5

∵ x = 5

∴ f(5) =   + 6(5) - 3.2584

∴ f(5) = 49.1

7 0
3 years ago
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