Which of the following is a solution of 4x2 = − 9x − 4?

2 answers:

8 0

The solution is -0.609611 and -1.64, I do not think you can simply find this by factoring but the only way is graphing it

RoseWind [281]3 years ago

6 0

Answer: The solutions are:

x1 = (- 9 + √17)/8 = -0.6

x2 = (-9 - √17)/8 = -1.6

Step-by-step explanation:

We have the equation:

4*x^2 = -9x - 4

first we put all the terms in one side of the equation:

4x^2 + 9x + 4 = 0

now, we use the Bhaskara's equation to find the roots:

where for a function:

ax^2 + bx + c = 0

the roots are:

x = (-b +- √(b^2 - 4ac))/2a

where each root takes one of the possible signs of the square root.

so, in our case we have:

x = (-9 +- √(9^2 - 4*4*4))/(2*4) = (- 9 +- √17)/8

then the solutions are:

x1 = (- 9 + √17)/8 = -0.6

x2 = (-9 - √17)/8 = -1.6

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Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north

Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

$x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]$

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]