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nika2105 [10]
3 years ago
7

a frog made three jumps. The first was 12 5/6 inches. The second jump was 8 3/6 inches.the third jump was 15 1/6 inches. What wa

s the total distance the frog jumped?
Mathematics
1 answer:
bazaltina [42]3 years ago
4 0
12 5/6+ 8 3/6+ 15 1/6
77/6+ 51/6+ 91/6
(77+51+91)/6
 219/6
36 1/2..........
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Planet ruba has a population of 1 million alien planet Zamba has one hundred thousand million how many more aliens does planet r
Elena-2011 [213]
Let's put it into numbers:

Ruba: 1 000 000

Zamba: 100 000 000 000

Zamba has many more aliens than Ruba!!!

it has 100 000 000 000/1 000 000 =100 000 times more aliens,

in absolute numbers: 100 000 000 000 - 1000 000 =  =99 999 900 000

100 000 000 000
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7 0
3 years ago
Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case
olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> =  Mike will show up.

Given:

P(D^{c})=0.55\\P(M^{c})=0.45

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

                                                   =1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0
3 years ago
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If you flip two coins 16 times, what is the best prediction possible for the number of times both coins will land on tails?
mr_godi [17]

Answer:

2×16

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Step-by-step explanation:

hope it helps..

8 0
3 years ago
Plz answer DDDDDDDDDDDDDDDDDD! using the line plot
masya89 [10]

Answer:

a. 6

b. 9

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Step-by-step explanation:

a.

Range = greatest - smallest

Range = 85 - 79

Range = 6

b.

b > 81

82, 83, 84...

3 82s

4 83s

2 85s

3 + 4 + 2 = 9

c.

b = 83

4 83s

4

6 0
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A baker sold 120 banana muffins and 60 blueberry muffins what was the ratio of banana muffins to blueberry muffin sold and
andrew-mc [135]

Answer:

120:60 or :=to

Step-by-step explanation:

8 0
3 years ago
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