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3 years ago

Please help!!! I will give brainliest to the person who explains it

Mathematics

1 answer:

artcher [175]3 years ago

3 0

Since we know the degrees of the circle is 360, add all of the pieces together and set equal to 360
Solving you get x = 15.
When plugging 15 back into each expression we get 90, 160, and 110.
This means the triangle sides are all different so the triangle is scalene.

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Which shows the decimal 0.16 expressed as a fraction in simplest form?

nata0808 [166]

$0.\underbrace{16}_{2}=\dfrac{16}{1\underbrace{00}_{2}}=\dfrac{16}{100}=\dfrac{16:4}{100:4}=\dfrac{4}{25}$

3 0

4 years ago

Write an equation in point slope form for the given line

PtichkaEL [24]

Answer:

$\large\boxed{y-4=-\dfrac{1}{2}(x-1)}$

Step-by-step explanation:

Look at the picture.

The formula of a slope:

The point-slope form of an equation of a linear function:

$y-y_1=m(x-x_1)$

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have two points (1, 4) and (-3, 6). Substitute:

$m=\dfrac{6-4}{-3-1}=\dfrac{2}{-4}=-\dfrac{1}{2}\\\\y-4=-\dfrac{1}{2}(x-1)$

7 0

3 years ago

7. A population of starlings reproduces once per year. The annual geometric growth rate of the population is 4. The population h

Alik [6]

Answer:

$\boxed{1280}$

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

1. Find the general formula for the sequence

a₁ = 80

r = 4

The general formula is then

aₙ = 80(4)ⁿ⁻¹

Step 2. Find the population in 1984

You want the population at the end of the year.

However, the terms in the sequence represent the population at the beginning of the year

The end of the second year is the beginning of the third year, so you want to evaluate a₃

a₃ = 80(4)³⁻¹ = 80(4)²= 80 × 16 = 1280

$\text{There will be $\boxed{\mathbf{1280}}$ individuals at the end of 1984}$

7 0

3 years ago

What is 1 and 3/4 as an improper fraction

EastWind [94]

$\huge\boxed{\frac{7}{4}}$

First, turn $1$ into an improper fraction with a denominator of 4, which matches $\frac{3}{4}$ .

$\displaystyle 1 \frac{3}{4} = \frac{4}{4} + \frac{3}{4}$

Now, just add the numerators.

$\displaystyle \frac{4}{4} + \frac{3}{4} = \boxed{\frac{7}{4}}$

7 0

4 years ago

I need help with solving the equations by using substitution

Fittoniya [83]

Given:
y = -2x + 4
2y = -6x + 12

2y = -6x + 12
2(-2x + 4) = -6x + 12
-4x + 8 = -6x + 12
-4x + 6x = 12 - 8
2x = 4
x = 4/2
x = 2

y = -2x + 4
y = -2(2) + 4
y = -4 + 4
y = 0

2y = -6x + 12 ; x = 2 ; y = 0
2(0) = -6(2) + 12
0 = -12 + 12
0 = 0

3 0

3 years ago