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ivanzaharov [21]
1 year ago
7

Pedro was curious if circles AAA and BBB (with XXX and YYY being on each circle, respectively) were similar, so he tried to map

one figure onto the other using rigid transformations.
Pedro concluded:
"It's not possible to map circle AAA onto circle BBB using a sequence of rigid transformations, so the circles are not similar."
What error did Pedro make in his conclusion?
Choose 1 answer:

(Choice A)
A
One more transformation — a rotation — would map circle AAA onto circle BBB. So the circles are similar.

(Choice B)
B
One more transformation — a dilation — would map circle AAA onto circle BBB. So the circles are similar.

(Choice C)
C
There is no error. This is a correct conclusion.
Mathematics
1 answer:
Ede4ka [16]1 year ago
7 0

it is B the answer B yes B

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Find the term to term rules for the following sequences 28, 25 ,22, 19, 16
Hoochie [10]

Answer: -3n+31

Step-by-step explanation:

1. 28-55=3

25-22=3

22-19=3

19-16=3

This means that n = -3 as we are subtracting

2. We then do the opposite, we take the first number and we add 3 instead of taking it away we get 31.

That is how you get your answer

-3n+31

4 0
2 years ago
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Find the slope of<br> (14, 8) and (7, -6)
maksim [4K]

Answer:

The Slope = 2

Explanation:

Slope : Δy/Δx = 2/1 = 2

5 0
3 years ago
Calculate the ratio of surface area to volume of an imaginary cubic cell measuring 4mm long on each side
Mkey [24]

Step-by-step explanation:

Surface area of cubic cell

= 6(side)^{2}  \\  = 6 \times  {4}^{2}  \\  = 6 \times 16 \\  = 96 \:  {mm}^{2}  \\  \\ volume \: of \:cubic \: cell  \\ =  {(side)}^{3}  \\  =  {4}^{3}  \\  = 64 \:  {mm}^{3} \\

Ratio of surface area to volume of imaginary cubic cell

= \frac{96}{64}\\ = \frac{3}{2}\\=3 : 2

5 0
3 years ago
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Find the measure of the remote exterior angle. m∠x=(4n−18)°m∠y=(n+9)°m∠z=(151−5n)° A. 71 B. 16 C. 100 D. 46
devlian [24]

Answer: A.71

Step-by-step explanation: 1.set up the equation

2. 4n-18+n+9=151-5n

3.combine like terms ->  5n-9=151-5n

4.solve for n

5.10n=160

n=16

now you have to plug 16 in for n in order to get the remote exterior angle.

151-5(16)

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7 0
3 years ago
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never [62]
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alpha = 1-C

So for instance, if the confidence level is C = 95% = 0.95 then alpha is 

alpha = 1-C
alpha = 1-0.95
alpha = 0.05

meaning we have a 5% significance level. The larger C gets, the smaller alpha gets and vice versa. It turns out that 0 < C < 1 and also 0 < alpha < 1. 

The closer C gets to 1, the alpha value gets closer to 0. The smaller alpha gets, the harder it is to reject the null. Why is that? If we have a fixed p value, say p = 0.02 then we reject the null if alpha > pvalue. But we fail to reject the null when alpha < pvalue. For very small alpha values, we're going to fail to reject H0 no matter how small the pvalue is. The pvalue would have to be really small for H0 to be rejected.

In short, I'm saying that if the confidence level is high, then the chance of rejecting the null hypothesis is low (or rare)

This is why the answer is choice A
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3 years ago
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