Question

A triathlon includes a .5 km swim, 40 km bike, and a 10 km run. Mr. B completed the swim in 25 minutes and 10 seconds, and the bike ride in 1 hour, 30 minutes, and 50 seconds. If he wants to equal the triathlon record of 2 hours and 46 minutes, how fast must Mr. B run in meters per second?

Answer 1

Answer:

3.33 meters per second

Step-by-step explanation:

you must find the total time that Mr. B spent to complete the swim and bike.

Information:

0h 25' 10'' ---------> Swim

1h 30' 50'' ---------> Bike

$hours = 0 + 1 = 1\\minutes = 25+30 = 55\\seconds = 10+50=60$

he spent 1h 55' 60'', this is 1h 56'.

now you must substract this time from the record time to find the time alloted to run:

first you convert both times into minutes:

$record \ time = 2(60) + 46 = 166 \ minutes \ \ \ \ multiply \ hours \ by \ 60 \ minutes\\time\ swim \ and \ bike = 1(60) + 56 = 116 \ minutes$

now substracting:

$time \ to \ run \ = record \ time \ - \ time \ swim \ and \ bike\\time \ to \ run \ = 166 - 116 = 50 \ minutes$

so he must travel 10 km in 50 minutes, that is:

speed = distance/time

$speed = \frac{10}{50} \frac{km}{min}$

1 km is equal to 1000 meters and 1 minute is equal to 60 seconds.

$speed = \frac{(10)}{(50)}\frac{(1000) meters}{(60) sec}\\\\speed = \frac{(10000)}{(3000)}\frac{meters}{sec} \ \ \ \ \ \ \ \ \ multiply \\\\speed = 3.33 \ meters/sec$

so Mr.B's speed must be 3.33 meters/sec