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Rus_ich [418]
3 years ago
7

See the picture below

Mathematics
1 answer:
svetlana [45]3 years ago
6 0

Answer:

a) 204.20 square centimeters

b) 282.74 square centimeters

c) 314.16 cubic centimeters

Step-by-step explanation:

a)

The curved surface area of a cone is given by:

Curved Surface Area of Cone =  \pi rl

Where r is the radius (given as 5) and l is the slant height, the hypotenuse of the right triangle formed (right side) with 5 as base and 12 as height.

We can find the slant height by using pythagorean theorem on the triangle:

12^2 + 5 ^2 = l^2

144 + 25 = l^2

169 = l^2

l = 13

Now,

Curved Surface Area of Cone = \pi rl=\pi (5)(13) = 204.20 square centimeters

b)

Total surface area is curved surface area PLUS the area of the bottom, which is a circle with area  \pi r^2

So the bottom has an area of  \pi r^2 = \pi (5)^2 = 78.54

Hence, The total surface area = 204.20 + 78.54 = 282.74 square centimeters

c)

The volume of cone is given by  \frac{1}{3}\pi r^2 h

Where radius is 5 and height is 12, so we have:

Volume of Cone = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (5)^2 (12) = 314.16 cubic centimeters

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The thirds of a number plus 5 is greater than 12
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Answer:

12

Step-by-step explanation:

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4 years ago
A sanitary landfill has available space of 16.2 ha at an average depth of 10 m. Seven hundred sixty-five (765) cubic meters of s
AfilCa [17]

Answer:

16.3 years

Step-by-step explanation:

1 ha = 10,000 m^2

The total capacity of the landfill is:

C = 16.2*10,000*10 = 1,620,000\ m^3

If waste is compacted to twice its delivered density, its volume is half of the delivered volume. Assuming that a year has 52 weeks, the volume of compacted solid waste dumped per year is:

V=52*(5*0.5*765)\\V=99,450\ m^3

The expected life of the landfill is given by its capacity divided by the yearly volume:

L=\frac{C}{V}=\frac{1,620,000}{99,450} \\L=16,3\ years

The landfill has an expected life of 16.3 years.

6 0
3 years ago
What is the answer to the problem?
matrenka [14]

Answer:

a

Step-by-step explanation:

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5 0
3 years ago
70 POINTS!!!!!!!!!! Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ
Likurg_2 [28]

Answer:

The measures of angles of triangle EFQ are

1) m\angle EFQ=100\°

2) m\angle FEQ=66\°

3) m\angle EQF=14\°

Step-by-step explanation:

step 1

Find the measure of arc QD

we know that

The inscribed angle is half that of the arc it comprises.

m\angle DFQ=\frac{1}{2}(arc\ QD)

substitute the given value

10\°=\frac{1}{2}(arc\ QD)

20\°=(arc\ QD)

arc\ QD=20\°

step 2

Find the measure of arc FQ

we know that

arc\ QD+arc\ FQ+arc\ EF=180\° ---> because ED is a diameter (the diameter divide the circle into two equal parts)

substitute the given values

20\°+arc\ FQ+28\°=180\°

arc\ FQ=180\°-48\°=132\°

step 3

Find the measure of angle EFQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EFQ=\frac{1}{2}(arc\ QD+arc\ ED)

substitute the given value

m\angle EFQ=\frac{1}{2}(20\°+180\°)=100\°

step 4

Find the measure of angle FEQ

we know that

The inscribed angle is half that of the arc it comprises.

m\angle FEQ=\frac{1}{2}(arc\ FQ)

substitute the given value

m\angle FEQ=\frac{1}{2}(132\°)=66\°

step 5

Find the measure of angle EQF

we know that

The inscribed angle is half that of the arc it comprises.

m\angle EQF=\frac{1}{2}(arc\ EF)

substitute the given value

m\angle EQF=\frac{1}{2}(28\°)=14\°

5 0
4 years ago
Which situation could be modeled by the expression 13÷5 ?
Rasek [7]

D. Is the answer because its the only one that makes sense.

8 0
3 years ago
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