Question

Choose the correct simplification of the expression the quantity a to the 3rd power over b to the 7th power all raised to the 2nd power. a to the 5th power over b to the 9th power a over b to the 14th power a to the 6th power over b to the 14th power a6b14

Answer 1

$(\frac{a^3}{b^7})^2=\frac{a^{3 \times 2}}{b^{7\times2}}= \frac{a^6}{b^{14}}$

Answer 2

(a^3/b^7)^2
Bring the power of 2 into the numerator and denominator.
a^6/b^14