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kolbaska11 [484]
3 years ago
13

Help having trouble, its quite easy.

Mathematics
2 answers:
EastWind [94]3 years ago
8 0

I believe it's C because 15 with an exponent of 5 is 15 x 15 x 15 x 15 x 15.

So that's basically larger than 15 x 15 x 15 x 15.

Common sense.

Schach [20]3 years ago
5 0

C  because 15 over 5 is equal to 15 five times and in C it is shown only 4 times so 15 over 5 <15 over 4. (C)

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Find the equation for the linear function that passes through the points (−2,−5) and (4,4). State your equation with whole numbe
UNO [17]

Answer:

y=\frac{3}{2} x-2

Step-by-step explanation:

To find your slope using two points, use the slope formula.

\frac{y2-y1}{x2-x1}

Your y1 term is -5, your y2 term is 4.

Your x1 term is -2, your x2 term is 4.

\frac{4-(-5)}{4-(-2)} \\\\\frac{9}{6} \\\\\frac{3}{2}

Now that we have your slope, you can use the slope and one of your points in point-slope form to find your y-intercept.

y-y1=m(x-x1)\\y-4=\frac{3}{2} (x-4)\\y-4=\frac{3}{2} x-6\\y=\frac{3}{2} x-2

4 0
3 years ago
SunDrop Candies Inc claims that their 3 ounce bag of candies contains over 90 pieces of candy.
nlexa [21]

Answer:

a) X~N(μ;σ²)

b) [87.695 ; 89.464]

c) and d) check the explanation below

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the claim of the company is correct and the 3-ounce bags of candies contain over 90 pieces of candy.

For this, a sample of 26 bags was taken and the number of candies per bag was counted.

The study variable is X: number of candy pieces in a 3 ounces bag.

a)

Using the sample data I've made a Shapiro-Wilks test,

H₀: X has a normal distribution

H₁: X doesn't have a normal distribution

α: 0.05

p-value: 0.5675

Since the p-value is greater than the significance level, we can assume that the study variable has normal distribution:

X~N(μ;σ²)

b)

To make this confidence interval, considering I only have sample data, I choose to use the Student t statistic.

Sample mean X[bar]= 88.58

Sample standard deviation S= 2.19

t_{n-1;1-\alpha/2} = t_{25;0.975} = 2.060

The formula for the interval is:

X[bar] ± t_{n-1;1-\alpha/2} * (S/√n)

88.58 ± 2.060 * (2.19/√26)

[87.695 ; 89.464]

c)

With a confidence level of 95%, you'd expect that the interval [87.69; 89.46] contains the value of the population mean of the number of candy pieces in a 3 ounces bag.

d)

The SunDrop Candies' claim is that their 3 ounces bag contains over 90 pieces of candy. Symbolically: μ > 90

Since their claim would lead to a one-tailed hypothesis test and the calculated confidence interval is two-tailed, you cannot use it to decide whether or not the company's claim is true. But, seeing as the two bonds of the interval are below 90 you could think that the company's claim is not correct. Of course this is just an idea, you must perform a statistical test to test if the company is wrong or not and, of course, have a statistical backing of your conclusions.

I hope it helps!

6 0
3 years ago
I hate math so much I can’t to be done with this class
Dafna11 [192]
Answer: y= 2 • (1/3)^x-2 -2
hope this helps!
5 0
3 years ago
Iready solve percent problems
e-lub [12.9K]

Answer:where is the question??.?

Step-by-step explanation:

5 0
2 years ago
What’s the answer to this
Aliun [14]

Answer:

v=9

Step-by-step explanation:

50 + x =180

x=130

130+(6v-4)= 180 (subtract 126 from each side)

6v=54 (divide by 6)

v=9

7 0
3 years ago
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