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4 years ago

Numerical Expressions -I need help to understand how to complete this example . Any help would be appreciated.

Mathematics

1 answer:

Natasha2012 [34]4 years ago

8 0

Basketball 16+2=18 (2*8)+2

Baseball 40-5=36 (5*8)-4

Softball 18+6=24 ( (5*8)-4)/2 +6

8+18+36+24=86

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An ant population starts at 1200 for a certain colony. As each month goes by in the winter, 6.5% of the population dies off. How

Nitella [24]

Answer:

There will be 916 ants alive after 4 months.

Step-by-step explanation:

Step 1

Let's change the percentage to a decimal by dividing by a 100.

6.5% / 100 = .065

Step 2

So, for the first month we will multiply the initial amount of ants by .065 and this will give us the number of ants that die.

1200 * .065 = 78

This means that after the first month, 1200 - 78 = 1122 ants will be alive.

Step 3

Now for the second month: 1122 * .065 = 72.93 (rounded to 73)

1122 - 73 = 1049 ants will be alive

Step 4

For the third month 1049 * .065 = 68.185 (rounded to 68)

1049 - 68 = 981 ants will be alive

Step 5

For the fourth month 981 * .065 = 63.765 (rounded to 64)

981 - 64 = 916 ants will be alive

Hope this helps!

5 0

3 years ago

Read 2 more answers

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

3 years ago

YO PLS HELP ASAP !!! MARKIN <br>BRAINIEST !!! btw da drop down answers are da same as whats shown

ale4655 [162]

Answer:

1. Is

2. Is

3. Is not

4. Is not

lol give me brainliest please!

8 0

4 years ago

F(x)=8_-4x-x^3. g(x)=x^2+7x-9. Find f(x)+g(x)

11111nata11111 [884]

$(8 - 4x - {x}^{3} ) + ( {x}^{2} + 7x - 9) \\ = - {x}^{3} + {x}^{2} - 4x + 7x + 8 - 9 \\ = - {x}^{3} + {x}^{2} + 3x - 1$
$(8x - 4x - {x}^{3} ) + ( {x}^{2} + 7x - 9) \\ - {x}^{3} + {x}^{2} + 8x - 4x + 7x - 9 \\ - {x}^{3} + {x}^{2} + 11x - 9$
The answer is either B, and you forgot to put in the ^2 in the answer choice, or C, and you forgot to put an x where there is a _ in the question.

Check the actual question (the one you recieved, not the one posted here) and see where the mistakes are. If f(x) = 8x - 4x - x^3, then your answer is C. However, if B is actually -x^3 + x^2 + 3x - 1, then the answer is B.

7 0

4 years ago

Please help meeeee I don’t really understand it

vredina [299]

3*3+4*4=x*x and 9+16=25 so x is 5 and then add other sides so 5+8+4+5

7 0

3 years ago