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HACTEHA [7]
3 years ago
6

Angle 2 and angle 3 are _______ angles? Need help ASAP​

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0
Supplementary angles
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Write 9020000 in standard form?
dolphi86 [110]

Answer:

9.02 x 10^6

Step-by-step explanation:

hope this helps!

8 0
3 years ago
Chris plans to mulch the Border surrounding a rectangular Garden in his backyard if the length of L of the garden (exculding its
Naya [18.7K]
The answer by the sequence:

Width of the garden = w
Length of the garden  = 2w+3

Width of the entire plot = w + 0.5w = 1.5w
Length of the entire plot = (2w + 3) 0.5w = 2.5w + 3

Area of the garden = w (2w + 3) 
Area of the entire plot = 1.5w (2.5w + 3)

Area of the garden = 2w² + 3w
Area of the entire plot = 3.75w² + 4.5w

Area of border = area of the entire plot - area of the garden
                          = 3.75w² + 4.5w - (2w² + 3w)

Area of the border = 3.75w² + 4.5w - 2w² - 3w

Area of the border = 1.75w² + 1.5w
3 0
3 years ago
If you received a score of 80% on an assignment,what is the ratio of correct answers to incorrect answers
Cerrena [4.2K]
Im not really sure so ill just give it a try.
mayeb 70? ten less"
6 0
3 years ago
Exercise 6.13 presents the results of a poll evaluating support for the health care public option in 2009, reporting that 52% of
sleet_krkn [62]

Answer:

A sample size of 6755 or higher would be appropriate.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error M is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

52% of Independents in the sample opposed the public option.

This means that p = 0.52

If we wanted to estimate this number to within 1% with 90% confidence, what would be an appropriate sample size?

Sample size of size n or higher when M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.52*0.48}{n}}

0.01\sqrt{n} = 0.8218

\sqrt{n} = \frac{0.8218}{0.01}

\sqrt{n} = 82.18

\sqrt{n}^{2} = (82.18)^{2}

n = 6754.2

A sample size of 6755 or higher would be appropriate.

3 0
3 years ago
Complete the equation for the line
Serggg [28]

Answer:

Yes

Step-by-step explanation:

4 0
3 years ago
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