On solving the equation, we get the following values of x- 5/6, -5/6 and √-1.
If there exists an equation of the form (x-a)(x-b) = 0, then (x-a) and (x-b) are known as the factors of the equation and x = a and x =b are the roots of the equation.
Here, we are given -3 (36x^2 - 25) (x^2 + 1) = 0
We can find the value of x by equating each of the terms to 0
if (36x^2 - 25) = 0
⇒ 36x^2 = 25
x^2 = 25/36
x = sqrt(25/36)
x = 5/6 or x = -5/6
Similarly, if (x^2 + 1) = 0
⇒ x^2 = - 1
⇒ x = sqrt(- 1)
This will come out to be an imaginary number, since square root of negative numbers are not real. √
Thus, the values of x are- 5/6, -5/6 and √-1.
Learn more about factorizing equations here-
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