Since you know that when x = 2, y = 8, when you replace x with xb:
<span>8=(xb<span>)3</span></span>
x has been replaced by xb, so xb must equal 2
and then substituting in 0.5 for x, you can solve for b
<span><span>0.5b=2</span></span>
You have a function that for every well-behaved day adds $1. Let's call x the well-behaved days and y the amount of money in the fund. We can then make a table that looks like this:
X (well behaved days) , Y (money in fund)
0, 0
1, 1
2, 2
3, 3
4, 4
5, 5
If you take these as points: (0,0), (1,1), (2,2) , ... and plot them you get a line. The relationship is linear.
Another way you can tell is that y = x which is the equation of a line with slope = 1 and y-intercept 0 although for this case we only focus on x values that are 0 or greater because there would not be a negative number of well-behaved days.
A third way you can tell is that the money in the fund increases by the same amount (1) for each well-behaved day. That is, it's rate of change is constant (always 1) and so it is linear...it has a constant rate of change or a constant slope.
Answer:
I believe the answer is model
Hope this helps <3
$21.30. You just have to add the numbers together.