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Vlada [557]
3 years ago
9

Which two binomials in part A didn't have an equivalent factored form? What made these expressions different from the three that

you could factor?​
Mathematics
1 answer:
ycow [4]3 years ago
6 0

Answer:

The binomials 16x2 + 9 and x2 + 16 didn’t have an equivalent factored form. Both are sums of perfect squares instead of differences.

Step-by-step explanation:

Official answer

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A three-digit number has tens digit two greater than the units digit and the hundreds digit one greater than the tens digit. The
Paha777 [63]

Answer:

875

Step-by-step explanation:

As given, there is a three digit number

So, let assume three digit number be `xyz`.

Now, as given tens digit is 2 greater than the unit digit.

∴ y= 2+z

Next, the hundred digit one greater than the tens digit.

∴x= 1+y

The sum of the tens and the hundreds digits is three times the units digit.

∴x+y= 3z

Now, substituting the value in the equation.

x+y= 3z

⇒ (1+y)+y= 3\times (y-2)

solving it to get value of y

⇒ 2y+1= 3y-6

⇒-y= -7

∴ y=7

Next, finding value of z

y= 2+z

substituting the value of y and subtracting both side by 2

∴ z= 7-2= 5

Last, finding the value of x

x=1+y

substituting the value of y

∴ x= 8

xyz= 875

5 0
3 years ago
Find the y-intercept of f(x) = x^3 + 3x^2 - X-3<br> HURRY
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Answer:

y-intercepts: (-3,0) , (-1,0) , (1,0)

Step-by-step explanation:

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3 years ago
0.29 divided by 1.3978
bixtya [17]

Answer:

0.20746887966

Step-by-step explanation:

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3 years ago
Does anyone have a spare essay of a famous mathematician? If you do pm me
Gnesinka [82]
What kind of spare essay though??
like what does it have to include?
<span />
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5 1/10-1 7/10=<br><br>A.3 3/5<br>B.6 4/5<br>C.3 2/5<br>D. 3 3/10<br><br>​
Alenkasestr [34]
The answer is C

You're welcome
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