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Arisa [49]
3 years ago
11

The code segmentif (speed <= 40)cout << "Too slow";if (speed > 40 && speed <= 55)cout << "Good spee

d";if (speed > 55)cout << "Too fast";could be written equivalently asif (speed <= 40)cout << "Too slow";else if (speed <= 55)cout << "Good speed";elsecout << "Too fast";A. TrueB. False
Computers and Technology
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer:

True is the correct answer for the above question.

Explanation:

  • The first code has three if statement, in which first if statement is true for the value of the speed which is less than or equal to 40 which can be false when the value of the speed can be greater than 40.
  • The if-statement clause also has a scenario where, if and else-if is used, in which the else-if statement will check when the if statement if being false.
  • So when the first if statement is false, then it is understood by the compiler that the value of the speed is greater than 40, which is no need to check in the else-if statement which is stated in the second code of the question.
  • Hence the first and the second code of the question gives the same result which is asked by the question. So the answer is true.
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Using the scenario below, answer the following questions:
4vir4ik [10]

Answer:

Here is code in java.

import java.util.*;

class Main

{

public static void main (String[] args) throws java.lang.Exception

{

   try{

         boolean flag=false;

         int total_mile=0;

         double avg_mile;

       // part 1, create and initialize array

       int inp[]={2,5,9,11,13,17,20,22,24,26};

       

       System.out.print("miles ran per week: ");

       // print the miles per week of train

       for(int x=0;x<10;x++)

       {

       System.out.print(inp[x]+" ");

       }

        System.out.println();

       //part 2, print the value of index 2 in the list

       System.out.println("value at index 2: "+inp[2]+" miles");

       //part 3, find length of array

       System.out.println("list length: "+inp.length);

     

       // part 4, calculate total mile and average

       for(int y=0;y<10;y++)

       {

       total_mile=total_mile+inp[y];

       }

       System.out.println("total miles ran: "+total_mile+" miles");

       

       avg_mile=total_mile/10.0;

       System.out.println("average no of miles ran= "+avg_mile+" miles");

       

     // part 5, check 4 exist in the list or not

       for(int k=0;k<10;k++)

       {

       if(inp[k]==4)

       {

       flag=true;

       break;

           }

       }

           if(flag)

           System.out.println("4 exist in the list.");

           else

            System.out.println("4 doesn't exists in the list.");  

       

   }catch(Exception ex){

       return;}

}

}

Explanation:

Create and initialize array with list value equals to 2 and maximum value 26. Print the miles of each week.Then find the value of miles at index 2 in the list.Next find the length of the array and print it.Calculate total miles ran of 10 weeks.Then calculate the average miles by dividing the total with 10. In the array, check 4 exist or not.

Output:

miles ran per week: 2 5 9 11 13 17 20 22 24 26                                                                            

value at index 2: 9 miles                                                                                                  

list length: 10                                                                                                            

total miles ran: 149 miles                                                                                                

average no of miles ran= 14.9 miles                                                                                        

4 doesn't exists

3 0
3 years ago
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