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Arisa [49]
3 years ago
11

The code segmentif (speed <= 40)cout << "Too slow";if (speed > 40 && speed <= 55)cout << "Good spee

d";if (speed > 55)cout << "Too fast";could be written equivalently asif (speed <= 40)cout << "Too slow";else if (speed <= 55)cout << "Good speed";elsecout << "Too fast";A. TrueB. False
Computers and Technology
1 answer:
Black_prince [1.1K]3 years ago
3 0

Answer:

True is the correct answer for the above question.

Explanation:

  • The first code has three if statement, in which first if statement is true for the value of the speed which is less than or equal to 40 which can be false when the value of the speed can be greater than 40.
  • The if-statement clause also has a scenario where, if and else-if is used, in which the else-if statement will check when the if statement if being false.
  • So when the first if statement is false, then it is understood by the compiler that the value of the speed is greater than 40, which is no need to check in the else-if statement which is stated in the second code of the question.
  • Hence the first and the second code of the question gives the same result which is asked by the question. So the answer is true.
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#include <iostream>

using namespace std;

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{

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Explanation:

Here, I'll explain some difficult lines (one after the other)

The italicized represents the function that returns the number of feet

<em>int convert(float miles) </em>

<em>{ </em>

<em>    return miles * 5280; </em>

<em>} </em>

The main method starts here

int main() {

The next two lines gives an info about the program

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

This line prompts user for number of miles

   cout<<"How many miles did you walk?. ";

   cin>>miles;

This line calls the function that converts miles to feet and prints the feet equivalent of miles

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

This line prompts user for another conversion

   cout<<"Continue? (y/n): ";

   cin>>response;

This is an iteration that repeats its execution as long as user continue input y as response

<em>    while(response == 'y') </em>

<em>    { </em>

<em>    cout<<"How many miles did you walk?. "; </em>

<em>    cin>>miles; </em>

<em>    cout<<"You walked "<<convert(miles)<<" feet"<<endl; </em>

<em>    cout<<"Continue? (y/n): "; </em>

<em>    cin>>response; </em>

<em>    } </em>

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