For all the answers I will assume that all buttons both green and blue must be used.
For the first question we will start by searching all the divisors of 16;
16: 1, 2, 4, 8, 16
We will think about the numbers of green buttons that can be used as the divisors of 16. We will check if t<span>he dividend of 16 to its divisors is a divisor for 56.
</span>
1 => 16 vests with 1 green button 56/16 = 3.5
2=> 8 vests with 2 green buttons 56/8 = 7
4=> 4 vests with 4 green buttons 56/4 = 14
8=> 2 vests with 8 green buttons 56/2 = 28
16=> 1 vest with 16 green buttons 56/1 = 56
From all the above results we concluded that Lee can make:
8 vests with 2 green buttons and 7 blue buttons
4 vests with 4 green buttons and 14 blue buttons
2 vests with 8 green buttons and 28 blue buttons
1 vest with 16 green buttons and 56 blue buttons
For the second question, the <span>greatest number of vests represents the greatest common divider of 16 and 56.
</span>First, we break into prime factors
16 = 2^4
56 = 2^3 *7
The greatest common divider is 8.
<span>Lee can make 8 vests and each one will have 2 green buttons and 7 blue buttons (16/8=2 and 56/8=7)</span>
Answer:
1.7
Step-by-step explanation:
Answer:
1-1/3 if its 14
1/52 if its 1/4
Step-by-step explanation:
16 is 10 +6, and 34 is 30+4
10*30=300
10*4=40
6*30=180
4*6=24
add them up: 300+40+180+24=544
Using an array to break
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