Area= legnth times width
or sometimes
area=legnth times height
area=measure1 times measure 2 on a flat plane
dependson the names
area=27
height=6
area=legnth times height
subsitute
27=legnth times 6
divide both sides by 6
27/6= legnth
simplified to 4 and 3/4
legnth=4 and 3/4 meter
subsitute
Answer:
x - 10 = 28
Step-by-step explanation:
10/8 in simplest form:
First, we can start off by finding the GCF of the denominator and the numerator. To do so, we need to list the factors of each of them and find the common ones.
Factors of 10: 1, 2, 5, 10
Factors of 8: 1, 2, 4, 8
We can see that our common factors are 1 and 2, considering that both the numerator and denominator has the same factors (1 and 2). Since we have our common factors, we need to find the greatest. Which is the greatest out of 1 and 2? The GCF is 2 because it is bigger than 1.
Second, divide the numerator and the denominator by the GCF (2).

Third, now we can revise our fraction and turn it into the simplest form. Take the two numbers you just got above us and put them in their numerator and denominator spot. You should get:

Answer in fraction form:

Answer in decimal form:

Answer in mixed number form:
What are the values of mode and median in the following set of numbers? 1,3,3,6,6,5,4,3,1,1,2 Mode: 1, 2, Median: 2 Mode: 1,3, M
AURORKA [14]
<h3><u>given</u><u>:</u></h3>
<u>
</u>
<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>
the mode and median of the given numbers set.
<h3><u>solution</u><u>:</u></h3><h3><u>mode</u><u>:</u></h3>
the most frequently occurred number.

<h3><u>median</u><u>:</u></h3>
first arrange all the numbers in either decending or ascending order, then find the number in the middle.


<u>hence</u><u>,</u><u> </u><u>the</u><u> </u><u>median</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>following</u><u> </u><u>data</u><u> </u><u>set</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>the</u><u> </u><u>mode</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>and</u><u> </u><u>3</u>
Answer:
x x=-4 y=x+2
Step-by-step explanation: