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4 years ago

What are 5 fractions that can simplify to 2/5

Mathematics

2 answers:

enot [183]4 years ago

6 0

4/10
8/20
16/40
32/80
64/160

Ede4ka [16]4 years ago

6 0

4/10

6/15

18/45

8/20

16/40

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4(x-5)<16 helppp i’m really bad at math

muminat

Answer:

x < 9

Step-by-step explanation:

Distribute 4

4x -20 < 16

add 20 to both sides

4x<36

divide by 4

x<9

6 0

3 years ago

How much is 2/3 × 5

djverab [1.8K]

Answer:

Answer:3.33 

Answer:3.33 Step-by-step explanation:

The answer is 3.33

2/3 × 5 = 3.33

5 0

3 years ago

Read 2 more answers

You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl

gtnhenbr [62]

Answer:

maximum difference of radii = $(r-R)=\frac{1}{2\pi ^{2}}$

Step-by-step explanation:

We know that area of circle is given by

$A=\pi \times (radius)^{2}$

For circle with radius 'r' we have

$A_{1}=\pi \times (r)^{2}$

For circle with radius 'R' we have

$A_{2}=\pi \times (R)^{2}$

Now according to given condition we have

$A_{1}-A_{2}\leq \frac{5}{\pi }$

$\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}$