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sdas [7]
3 years ago
6

Circle A has a diameter of approximately 20 inches and an area of approximately 300 in2.

Mathematics
1 answer:
Katena32 [7]3 years ago
7 0

Answer:

4. About 2,700 in2

Step-by-step explanation:

The area of a circle (A), measured in square inches, is directly proportional to the square of its diameter (d), measured in inches. That is:

A \propto d^{2}

A = k\cdot d^{2}

Where k is the constant of proportionality, dimensionless.

In consequence, the following relationship between circles A and B is obtained:

\frac{A_{B}}{A_{A}} = \frac{d_{B}^{2}}{d_{A}^{2}}

The area of the circle B is now cleared:

A_{B} =\left(\frac{d_{B}}{d_{A}} \right)^{2}\cdot A_{A}

Given that d_{A} = 20\,in, d_{B} = 60\,in and A_{A} = 300\,in^{2}, then:

A_{B} = \left(\frac{60\,in}{20\,in} \right)^{2}\cdot (300\,in^{2})

A_{B} = 2700\,in^{2}

Therefore, the correct answer is 4.

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g(-7) = 5

Step-by-step explanation:

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Serggg [28]

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(8 * x) -14 = -11

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6 0
3 years ago
What is 77/200 as a decimal
garri49 [273]
<span>The correct answer is 0.385.

Explanation<span>:
Decimals deal with powers of 10, such as 10, 100, 1000, etc. We can change this to a power of 10 by dividing both top and bottom by 2; this will give us 100 in the denominator.

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8 0
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each of exercises 15–30 gives a function ƒ(x) and numbers l, c, and e 7 0. in each case, find an open interval about c on which
3241004551 [841]

The given inequality holds for the open interval (2.97,3.03)

It is given that

f(x)=6x+7

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We have,

|f(x)−L| = |6x+7−25|

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          = 6|x−3|

Now,

6|x−3| <0.18  then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03

the given inequality holds for the open interval (2.97,3.03)

For more information on inequality click on the link below:

brainly.com/question/11613554

#SPJ4

Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.

f(x)=6x+7,L=25,c=3,ϵ=0.18

 

.

6 0
1 year ago
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