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ElenaW [278]
3 years ago
12

Find the digit that 3, 71 _ divisible by 9?

Mathematics
2 answers:
marin [14]3 years ago
8 0
So you need to find three numbers divisible by 9 right? Explain the question a bit more. Like 3 sperate numbers that are divisible by 9 or 3 numbers that add up to a total that is divisible by 9?
Karolina [17]3 years ago
4 0
The digit that 3, 71 _ divisible by 9 is 4 and 7
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Find the value of k so that 48x-ky=11 and (k+2)x+16y=-19 are perpendicular lines.
Rufina [12.5K]

Answer: k = -1 +/- √769

<u>Step-by-step explanation:</u>

48x - ky = 11

<u>-48x        </u>  <u> -48x</u>

         -ky = -48x + 11

         \frac{-ky}{-k} = \frac{-48x}{-k} + \frac{11}{-k}    

           y =\frac{48x}{k} - \frac{11}{k}

Slope: \frac{48}{k}

*************************************************************************

 (k + 2)x + 16y = -19

<u>- (k + 2)x          </u>   -<u>(k + 2)x </u>

                 16y = -(k + 2)x - 19

                  \frac{16y}{16} = -\frac{(k + 2)x}{16} - \frac{19}{16}

                  y = -\frac{(k + 2)x}{16} - \frac{19}{16}

Slope: -\frac{(k + 2)}{16}

**********************************************************************************

\frac{48}{k} and -\frac{(k + 2)}{16} are perpendicular so they have opposite signs and are reciprocals of each other.  When multiplied by its reciprocal, their product equals -1.

-\frac{(k + 2)}{16} *  \frac{k}{48} = -1

\frac{(k + 2)k}{16(48)} = 1

Cross multiply, then solve for the variable.

(k + 2)(k) = 16(48)

k² + 2k - 768 = 0

Use quadratic formula to solve:

k = -1 +/- √769



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3 years ago
To use Long Division of Polynomials to verify that x = a/b is a zero on a polynomial function P(x), the divisor would be
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Answer:

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Step-by-step explanation:

If a/b is a zero, then (x -a/b) is a factor of the polynomial. That is, the value x=a/b will make a factor of the polynomial be zero.

The above factor can be written without fractions by multiplying it by b:

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