What is an equation of the line that passes through the point (-2,-3)(−2,−3) and is parallel to the line 5x+2y=14
1 answer:
Answer:
y=5/2x+2
Step-by-step explanation:
rearrage equation: y=5/2x-7
new slope is same: y=5/2x+b
substitue point (-2,-3):
-3=5/2(-2)+b
-3=-5+b
-3+5=b
2=b
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