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Hatshy [7]
2 years ago
8

What is an equation of the line that passes through the point (-2,-3)(−2,−3) and is parallel to the line 5x+2y=14

Mathematics
1 answer:
Semmy [17]2 years ago
5 0

Answer:

y=5/2x+2

Step-by-step explanation:

rearrage equation: y=5/2x-7

new slope is same: y=5/2x+b

substitue point (-2,-3):

-3=5/2(-2)+b

-3=-5+b

-3+5=b

2=b

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hram777 [196]

Answer:

They are both negative

Step-by-step explanation:

the given coordinate is in quadrant IV and when reflected over the y axis, quadrant IV becomes quadrant III which is (-,-)

7 0
3 years ago
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Can someone please help me with this. I'll give 50 points!
OlgaM077 [116]

Answer:

the second one

Step-by-step explanation:

7 0
3 years ago
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Solve each equation for the bold variable​
Phantasy [73]

Answer:

y = 3 - 2x

Step-by-step explanation:

The goal is to isolate the y variable

In order to have y by itself (on one side of the equation or equal sign), we must move the other numbers and variables to the other side.

Since 2x is on the same side as y, we have to subtract it from both sides. Subtracting it cancels out the original 2x and leaves the equation to look like this:

y = 3 - 2x

Now the y is isolated

Another example:

-5x + y = 15

To isolate the y, we must cancel out the -5x. Add 5x to both sides. It will cancel out the -5x and bring it to the right side of the equation, resulting in:

y = 15 + 5x

4 0
3 years ago
E=6c^2-2c-1<br> F=-4c^2+7c+5<br> E+F=
kifflom [539]

Answer:

E + F =   2c^2  + 5c + 4

Step-by-step explanation:

E=6c^2-2c-1

F=-4c^2+7c+5

E+F=  6c^2   -2c   -1  +  -4c^2   +   7c   +  5

E + F =   6c^2 - 4c^2  - 2c + 7c  - 1  + 5

E + F =   2c^2  + 5c + 4

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3 years ago
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