Minus 14 from both sides
x²-4x-14=0
use quadratic formula because we cant factor
for
ax²+bx+c=0
so
1x²-4x-14=0
a=1
b=-4
c=-14
the solutions are
x=2+√3 and
x=2-√3
Answer: 5 classes.
Step-by-step explanation:
You can use the rule to determine the number of classes for a frequency distribution.
The rule says that where
is the number of classes
is the number of the data points
We know that the number of data points is = 20.
Next, we start searching for so that we can get a number 2 to the that is larger that the number of data points.
This suggests that you should use 5 classes.
I assume the sentences:
"23 employees speak German; 29 speak French; 33 speak Spanish"
mean these speak ONLY the respective languages other than English.
Then the calculations boil down to those who speak ONLY two languages, noting that 8 speak French, German and Spanish, which need to be subtracted from
1. French and Spanish: 43-8=35 (speak only two foreign languages)
2. German and French: 38-8=30 (speak only two foreign languages)
3. German and Spanish: 48-8=40 (speak only two foreign languages).
Now We add up the total number of employees:
zero foreign language = 7
one foreign language = 23+29+33=85
two foreign languages = 30+35+40=105
three foreign languages=8
Total =7+85+105+8=205
(a) Percentage of employees who speak at least one foreign lanugage = (85+105+8)/205=198/205=.966=96.6%
(b) Percentage of employees who speak at least two foreign lanugages = (105+8)/205=113/205=.551=55.1%
Answer:
Option B will be your answer
Step-by-step explanation:
hope it helps
Answer: 100.8
Step-by-step explanation:
Given that:
Standard deviation (σ) = 16
X > 100
From the z table :
Zscore = P(X > 100) = - 0.05
Zscore = - 0.05
Thus ;
Zscore = (x - m) / σ
x = 100
-0.05 = ( 100 - m) / 16
-0.05 * 16 = 100 - m
- 0.8 = 100 - m
m = 100 + 0.8
Mean = 100. 8
Mean score = 100.8
